javascript 我想通过javascript隐藏基于PHPcondition的提交按钮
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I want to hide the submit button based on a PHPcondition through javascript
提问by iaaphpd13
<?php
if(mysql_num_rows($result5)>0)
{
echo 'condition matched';
// the above echo is just for testing
?>
<script type='text/javascript'>
document.getElementById("submitbtn").style.display = "none";
</script>
<?php
}
?>
here I am evaluating an if clause, if the condition is true, I want to hide the submit button of the form.
在这里我正在评估一个 if 子句，如果条件为真，我想隐藏表单的提交按钮。
<form action='xyz.php'>
<input type='text'>
<input type='text'>
<input type='text'>
<input type='submit' id='submitbtn' name='save' value='SAVE' class='form_btn' >
</form>
The condition is evaluating to true, but the submit button is still visible. How do I achieve this??
条件评估为真，但提交按钮仍然可见。我如何实现这一目标？
回答by Sahil Manchal
try using this way....
尝试使用这种方式....
<input type='submit' <?php if($result5->num_rows>0) {?> disabled="disabled" <?php } ?> id='submitbtn' name='save' value='SAVE' class='form_btn' >
may be it will help
可能会有所帮助
回答by gangzi
I had tied your code,and these worked ok, so I think must have other problems to affected your js code, such as a same name Id of submitbtn, or a js error.
我已经绑定了你的代码，这些工作正常，所以我认为肯定有其他问题会影响你的 js 代码，例如同名 Idsubmitbtn或 js 错误。
回答by Ishan Srivastava
Posting the answer because all others are just disabling the button. It will still be visible. So to hide the button, use:
发布答案是因为所有其他人都只是禁用按钮。它仍然是可见的。所以要隐藏按钮，请使用：
window.onload = function(){
document.getElementById("<id of your submit button>").style.display = "none";
}
inside the if(condition=true)
在 - 的里面 if(condition=true)
OR
或者
<input type='submit' name="sbmt" id="id_1"<?php if(condition=true) { ?> style="display: none" <?php } ?> />
but since your question has asked exceptionally for "javascript" i will go one step further and write
但由于您的问题特别要求“javascript”，我将更进一步写
<input type='submit' name="sbmt" id="id_1"
<?php if(condition=true) { ?>
<script type='text.javascript'>
document.getElementById("id_1").style.display = "none";
</script>
<?php } ?>
/>
回答by Happy Coding
If you want to use js try this :
如果你想使用 js 试试这个：
<?php
if(mysql_num_rows($result5)>0)
{
echo 'condition matched';
// the above echo is just for testing
?>
<script type='text/javascript'>
$(document).ready(function(){
document.getElementById("submitbtn").style.display = "none";
});
</script>
<?php
}
?>
You can achieve this by using php too.
您也可以通过使用 php 来实现这一点。
<input type='submit' id='submitbtn' name='save' value='SAVE' class='form_btn' <?php if(mysql_num_rows($result5)>0) echo 'style="display:none"';?>>
回答by AnkiiG
Try as below : jQuery must be there on your page.
尝试如下：jQuery 必须在您的页面上。
On calling the statement on page ready will solve the problem.
调用页面准备好的语句将解决问题。
<?php
if(mysql_num_rows($result5)>0)
{
echo 'condition matched';
// the above echo is just for testing
?>
<script type='text/javascript'>
$( document ).ready(function() {
document.getElementById("submitbtn").style.display = "none";
});
</script>
<?php
}
?>
回答by Loukoulele
<?php
if(mysql_num_rows($result5)>0)
{
echo'<div style='visibility:hidden' id="del">';
echo'<script>
$(document).ready(function(e) {
$("#del").css("visibility", "visible");
});
</script>';
}
?>
回答by Nabi
I Think you added your php codes before that formloads!
我认为您在form加载之前添加了 php 代码！
So you need window.onloadORReplace your php codes to after form
所以你需要window.onloadOR替换你的 php 代码到之后form
<?php
if(mysql_num_rows($result5)>0)
{
echo 'condition matched';
?>
<script type='text/javascript'>
window.onload = function(){
document.getElementById("submitbtn").style.display = "none";
}
</script>
<?php
}
?>
回答by Hearner
It is not noneit's :
不是none它是：
<script type='text/javascript'>
document.getElementById("submitbtn").style.visibility = "hidden";
</script>
