java Grails 智能获取战争 baseUrl？
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Grails get war baseUrl intelligently?
提问by Stefan Kendall
My baseUrl is http://localhost:8080/whatever. On other machines, it's http://localhost/whatever.
我的 baseUrl 是http://localhost:8080/whatever. 在其他机器上，它是http://localhost/whatever.
Is there a smart way to get this information without using
有没有一种聪明的方法来获取这些信息而不使用
<%
String baseUrl = "http://" + request.getServerName() + ":" + request.getServerPort() + request.getContextPath()
%>
I'm trying to dynamically create some links to path parameterized rest URLS, i.e:
我正在尝试动态创建一些指向路径参数化其余 URLS 的链接，即：
http://localhost:8080/a/b/${param1}/c/${param2}
http://localhost:8080/a/b/${param1}/c/${param2}
If there's a better way to do this, let me know.
如果有更好的方法来做到这一点，请告诉我。
回答by Hoàng Long
In case you forget, isn't that was answered in the question here. Just set the grails.serverURLand grails.app.contextin the configuration file of your deployed machine. Then use createLinkto make the URL. Or I missed something?
万一你忘记了，这里的问题不是已经回答了。只需在部署机器的配置文件中设置grails.serverURL和grails.app.context。然后createLink用来制作网址。或者我错过了什么？
回答by sebnukem
This solution doesn't require grails.serverURL to be set:
此解决方案不需要设置 grails.serverURL：
<g:createLink absolute='true' uri='/WHATEVER'/>or
<g:createLink absolute='true' uri='/WHATEVER'/>或者
${g.createLink(absolute:true, uri:"/WHATEVER")}
${g.createLink(absolute:true, uri:"/WHATEVER")}
will generate:
将产生：
http://HOST:PORT/APPNAME/WHATEVER
http://HOST:PORT/APPNAME/WHATEVER
Set the URIto point to where you want to in the app. Use '/'for the base URL of your app:
将URIto设置为您想要在应用程序中的位置。使用'/'你的应用程序的基本URL：
http://HOST:PORT/APPNAME/
http://HOST:PORT/APPNAME/
回答by Dana
the <g:link>tag accepts a parameter, "absolute=true", that will build a URL that respects the current environment's serverUrl and contextPath. I recommend combining that with a named URL mappingto build your URL.
所述<克：链路>标签接受一个参数，“绝对=真”，即将建立一个URL，它方面与当前环境的的serverUrl和contextPath中。我建议将其与命名 URL 映射结合起来构建您的 URL。
If you're unable to build your entire URL at page rendering time, Grails can still build part of the URL for you:
如果您无法在页面呈现时构建整个 URL，Grails 仍可以为您构建部分 URL：
var url = '${g.createLink(absolute: true, mapping: "mymappingname")}/' + param1 + '/c/' + param2;
console.log(url); // "http://localhost:8080/whatever/a/b/something/c/somethingelse"
And in UrlMappings.groovy:
在 UrlMappings.groovy 中：
class UrlMappings {
name mymappingname: "/a/b/$param1?/c/$param2?" {
controller = 'myRestHandler'
}
}
回答by user3461853
I solve using createLink(action: 'index', controller: 'Root', params: [id: id], absolute: true)
我使用 createLink(action: 'index', controller: 'Root', params: [id: id], absolute: true) 解决
