php Laravel Blade - 如果满足条件则添加一个类
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Laravel blade - Add a class if a condition is met
提问by Elaine Marley
This is simple but I can't seem to be able to do it with blade and I usually go back to php for this but, since I can't declare a new php variable with blade (without printing it, that is) how should I change a simple class name if a certain condition is met? Take this example of a link, I just want to add the class "active" if $hostess->active=1
这很简单，但我似乎无法使用刀片来做到这一点，我通常会为此返回 php，但是，因为我无法使用刀片声明一个新的 php 变量（即不打印它）应该如何如果满足某个条件，我会更改一个简单的类名吗？以这个链接为例，如果 $hostess->active=1，我只想添加类“active”
{{ HTML::linkRoute('hostesses.index', 'Archived', $params, array('class' => 'btn btn-default')) }}
I know how to do this with php, but how would it be done with blade?
我知道如何用 php 做到这一点，但如何用 Blade 做到这一点？
采纳答案by The Alpha
Something like this?
像这样的东西？
{{ HTML::linkRoute('hostesses.index', 'Archived', $params, array('class' => $hostess->active ? 'btn btn-info' : 'btn btn-default')) }}
回答by JP Blanco
You could do this:
你可以这样做：
// App/Http/routes.php
Route::get('foo/bar', 'FooController@bar);
// Your blade file
<li class="{{ Request::path() == 'foo/bar' ? 'active' : '' }}">
<a href="{{ url('foo/bar') }}"></i> Bar</a>
</li>
