bash 如何在shell脚本中以%Y%m%d格式打印两个日期之间的日期？
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How to print dates between two dates in format %Y%m%d in shell script?
提问by buzzinolops
I have two arguments as inputs: startdate=20160512and enddate=20160514.
我有两个参数作为输入： startdate=20160512和enddate=20160514。
I want to be able to generate the days between those two dates in my bash script, not including the startdate, but including the enddate:
我希望能够在我的 bash 脚本中生成这两个日期之间的天数，不包括开始日期，但包括结束日期：
20160513 20160514 I am using linux machine. How do I accomplish this? Thanks.
20160513 20160514 我使用的是 linux 机器。我该如何实现？谢谢。
回答by John1024
Using GNU date:
使用 GNU 日期：
$ d=; n=0; until [ "$d" = "$enddate" ]; do ((n++)); d=$(date -d "$startdate + $n days" +%Y%m%d); echo $d; done
20160513
20160514
Or, spread over multiple lines:
或者，分布在多行上：
startdate=20160512
enddate=20160514
d=
n=0
until [ "$d" = "$enddate" ]
do
((n++))
d=$(date -d "$startdate + $n days" +%Y%m%d)
echo $d
done
How it works
这个怎么运作
d=; n=0Initialize variables.
until [ "$d" = "$enddate" ]; doStart a loop that ends on
enddate.((n++))Increment the day counter.
d=$(date -d "$startdate + $n days" +%Y%m%d)Compute the date for
ndays afterstartdate.echo $dDisplay the date.
doneSignal the end of the loop.
d=; n=0初始化变量。
until [ "$d" = "$enddate" ]; do开始一个以 结束的循环
enddate。((n++))增加日计数器。
d=$(date -d "$startdate + $n days" +%Y%m%d)计算
n之后天的日期startdate。echo $d显示日期。
done发出循环结束的信号。
回答by Sanjeev
This should work on OSX, make sure your startdate is lesser than enddate, other wise try with epoch.
这应该适用于 OSX，确保您的开始日期小于结束日期，否则请尝试使用 epoch。
startdate=20160512
enddate=20160514
loop_date=$startdate
let j=0
while [ "$loop_date" -ne "$enddate" ]; do
loop_date=`date -j -v+${j}d -f "%Y%m%d" "$startdate" +"%Y%m%d"`
echo $loop_date
let j=j+1
done
回答by nisetama
Another option is to use dateseqfrom dateutils(http://www.fresse.org/dateutils/#dateseq). -ichanges the input format and -fchanges the output format.
另一种选择是使用dateseqfrom dateutils( http://www.fresse.org/dateutils/#dateseq)。-i更改输入格式并-f更改输出格式。
$ dateseq -i%Y%m%d -f%Y%m%d 20160512 20160514
20160512
20160513
20160514
$ dateseq 2016-05-12 2016-05-14
2016-05-12
2016-05-13
2016-05-14
