java ajax - 为什么 jquery 用空格（“”）替换“+”？
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ajax - Why jquery replaces "+" with a space (" ")?
提问by NinjaBoy
I am having a problem here. When I use ajax to pass a parameter containing "+" to my controller it is being replaced by a space.
我这里有问题。当我使用 ajax 将包含“+”的参数传递给我的控制器时，它被一个空格替换。
Example, I will pass value = Tom+Jerry+Garfieldusing ajax. When I use System.out.println() in my controller it displays Tom Jerry Garfield. I tried using other special characters I don't seem to have a problem.
例如，我将Tom+Jerry+Garfield使用 ajax传递 value = 。当我在控制器中使用 System.out.println() 时，它显示Tom Jerry Garfield. 我尝试使用其他特殊字符我似乎没有问题。
Please help. Thanks in advance.
请帮忙。提前致谢。
回答by compid
In some GETand POSTrequests (most likely in the URL, or via a form), spaces are encoded as "+" (plus) symbols before they are passed to the server. You can see this behaviour if you do a normal GETrequest - you will see something like google.com?q=test+exampleIf you want to pass a plus symbol via an ajax GET/POST request, you need to "urlencode" it. The URL encoded value for +is %2B.
在某些GET和POST请求中（最有可能在 URL 中，或通过表单），空格在传递到服务器之前被编码为“+”（加号）符号。如果您执行普通GET请求，您可以看到这种行为- 您会看到类似的内容google.com?q=test+example如果您想通过 ajax GET/POST 请求传递加号，您需要对其进行“urlencode”。对于URL编码值+是%2B。
Also note:
另请注意：
The javascript encodeURIComponent() function can be used, as answered in:
可以使用 javascript encodeURIComponent() 函数，如下所述：
回答by xdazz
+is decoded as space after url decoding. If you want to pass +, you need to encode it.
+url解码后被解码为空格。如果要通过+，则需要对其进行编码。
回答by bhuvin
When we pass values to the controller there is a model binder which is sitting in between the request. When the ajax call is made the url and the request is encoded. The " " (Space) character in url decoded form encodes to a "+".
The Model Binder on the other hand decodes the request and extracts the parameters and gives it to the controller and hence "+" is converted to a " " .
But here the question is why would one pass "+" as a separator ??
当我们将值传递给控制器时，有一个模型绑定器位于请求之间。当进行 ajax 调用时，url 和请求被编码。url 解码形式的“”（空格）字符编码为“+”。
另一方面，模型绑定器解码请求并提取参数并将其提供给控制器，因此“+”被转换为“”。但这里的问题是为什么要通过“+”作为分隔符？
