C语言 在 C 中将一个数组的元素复制到另一个数组
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Copy elements of one array to another in C
提问by Rozen
So I am trying to use char array in C to copy from one array to another, each element at a time, however, I am stuck at this part. I did try to research but may be I'm a dumb or what not, I still could not get it right. Here is my code:
所以我试图在 C 中使用 char 数组从一个数组复制到另一个数组，一次每个元素，但是，我被困在这部分。我确实尝试过研究，但可能是我是个笨蛋还是什么不是，我仍然无法做对。这是我的代码：
Say I have two array
说我有两个数组
char arr1[1000][3]
char arr2[1000][3]
So wHat I mean is that [3] equal length of the string and each array has 1000 elements. So arr1[0] = "AB\0"
所以我的意思是 [3] 等长的字符串和每个数组有 1000 个元素。所以arr1[0] = "AB\0"
I can't, obviously, do arr1[i] = arr2[i];won't work of course, I did try strcpy but don't quite get it right. Please help me out a bit, thank you :)
我不能，显然，arr1[i] = arr2[i];当然不会工作，我确实尝试过 strcpy 但不太正确。请帮我一下，谢谢:)
Here a portion of it, the specific function I writing: Please just answer the one I ask, I can do this easily in Java but I really learning C so... An example would be nice :D
这是它的一部分，我编写的特定功能：请回答我问的问题，我可以用 Java 轻松完成此操作，但我真的在学习 C，所以......一个例子会很好：D
//build stacks
card_pos_ptr add_card(card_pos_ptr head, char card_list[1000][3], int index){
int i,k = 0;
int start_index = index;
card_pos_ptr current = head;
for(i=0;i<13;i++){
for(k=0;k<4;k++){
if(current->card_stack == NULL){
card_ptr node = (card_ptr)malloc(sizeof(card));
strcpy(node->card_name,);
node->up = false;
node->down = NULL;
start_index++;
}else{
card_ptr node = (card_ptr)malloc(sizeof(card));
//node->card_name[0] = card_list[start_index];
node->up = false;
node->down = current->card_stack;
current->card_stack = node;
start_index++;
}
}
current = current->next_pos;
}
}
回答by Wald
Not sure what you are trying to do with this declaration but in frist place to declare array you need something like :
不确定你想用这个声明做什么，但在第一个地方声明数组你需要像这样的东西：
char arr1[1000][3];
char arr1[0][0] = 'A';
char arr1[0][0] = 'B';
...
And in order to copy each element one at a time use a for loop:
为了一次复制一个元素，请使用 for 循环：
if ( something that determines X ? ) {
for ( int i=0; i < 3 ; i++ ) {
arr2[x][i] = arr1[x][i];
}
}
回答by Cyborg-X1
I would do it like this:
我会这样做：
int i;
char arr1[1000][3];
char arr2[1000][3];
arr1[0][0]='v';
for(i=0;i<1000;++i)
{
strncpy(arr2[i],arr1[i],3); //safe copy, copies max. 3 chars.
}
printf("%c\n",arr2[0][0]);
回答by Srikanth
Try
尝试
memcpy( &node->card_name[0] ,card_list[start_index])
memcpy( &node->card_name[0] ,card_list[start_index])
