递归计算特定文件 BASH
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Recursively count specific files BASH
提问by jamesy
My goal is to write a script to recursively search through the current working directory and the sub dirctories and print out a count of the number of ordinary files, a count of the directories, count of block special files, count of character special files,count of FIFOs, and a count of symbolic links. I have to use condition tests with [[ ]]. Problem is I am not quite sure how to even start.
我的目标是编写一个脚本来递归搜索当前工作目录和子目录，并打印出普通文件数、目录数、块特殊文件数、字符特殊文件数、计数FIFO 的数量，以及符号链接的数量。我必须对 [[]] 使用条件测试。问题是我不太确定如何开始。
I tried the something like the following to search for all ordinary files but I'm not sure how recursion exactly works in BASH scripting:
我尝试了以下类似的方法来搜索所有普通文件，但我不确定递归在 BASH 脚本中究竟是如何工作的：
function searchFiles(){
if [[ -f /* ]]; then
return 1
fi
}
searchFiles
echo "Number of ordinary files $?"
but I get 0 as a result. Anyone help on this?
但结果我得到了 0。有人帮忙解决这个问题吗？
回答by MattH
Why would you not use find?
你为什么不使用find？
$ # Files
$ find . -type f | wc -l
327
$ # Directories
$ find . -type d | wc -l
64
$ # Block special
$ find . -type b | wc -l
0
$ # Character special
$ find . -type c | wc -l
0
$ # named pipe
$ find . -type p | wc -l
0
$ # symlink
$ find . -type l | wc -l
0
回答by Fredrik Pihl
Something to get you started:
一些让你开始的东西：
#!/bin/bash
directory=0
file=0
total=0
for a in *
do
if test -d $a; then
directory=$(($directory+1))
else
file=$(($file+1))
fi
total=$(($total+1))
echo $a
done
echo Total directories: $directory
echo Total files: $file
echo Total: $total
No recursion here though, for that you could resort to ls -lRor similar; but then again if you are to use an external program you should resort to using find, that's what it's designed to do.
不过这里没有递归，因为你可以求助于ls -lR或类似的方法；但话说回来，如果您要使用外部程序，您应该求助于 using find，这就是它的设计目的。
