java 如何在 Oracle ADF 中使用 af:inputFile 上传文件
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How to upload a file using af:inputFile in Oracle ADF
提问by Abdul
Can anyone please tell me how to upload file to server using af:inputFile in Oracel ADF. I searched about this and found we can use the following
谁能告诉我如何在 Oracel ADF 中使用 af:inputFile 将文件上传到服务器。我搜索了这个，发现我们可以使用以下内容
<af:form usesUpload="true">
<af:inputFile columns="10"
valueChangeListener="#{backing.fileUploaded}"/>
</af:form>
using the above code I can set a method that executes when some choose some file in the form. So now I need to know in fileUploaded method what should be the java code to upload the given file to the server.
使用上面的代码，我可以设置一个方法，该方法在某些人选择表单中的某个文件时执行。所以现在我需要在 fileUploaded 方法中知道将给定文件上传到服务器的 java 代码应该是什么。
Please help me. How I can achieve this.
请帮我。我如何才能做到这一点。
Thanks in advance.
提前致谢。
采纳答案by Ashish Awasthi
As you have already created value change listener in managed bean then use this code -
由于您已经在托管 bean 中创建了值更改侦听器，因此请使用此代码 -
/**Method to Upload File ,called on ValueChangeEvent of inputFile
* @param vce
*/
public void uploadFileVCE(ValueChangeEvent vce) {
if (vce.getNewValue() != null) {
//Get File Object from VC Event
UploadedFile fileVal = (UploadedFile) vce.getNewValue();
}
}
and this is the method to upload file on server (You have to provide absolute path)
这是在服务器上上传文件的方法（您必须提供绝对路径）
/**Method to upload file to actual path on Server*/
private String uploadFile(UploadedFile file) {
UploadedFile myfile = file;
String path = null;
if (myfile == null) {
} else {
// All uploaded files will be stored in below path
path = "D://FileStore//" + myfile.getFilename();
InputStream inputStream = null;
try {
FileOutputStream out = new FileOutputStream(path);
inputStream = myfile.getInputStream();
byte[] buffer = new byte[8192];
int bytesRead = 0;
while ((bytesRead = inputStream.read(buffer, 0, 8192)) != -1) {
out.write(buffer, 0, bytesRead);
}
out.flush();
out.close();
} catch (Exception ex) {
// handle exception
ex.printStackTrace();
} finally {
try {
inputStream.close();
} catch (IOException e) {
}
}
}
//Returns the path where file is stored
return path;
}
Check this thread on OTN Forum https://community.oracle.com/message/13135474#13135474
在 OTN 论坛上查看此主题 https://community.oracle.com/message/13135474#13135474
Here you can read full implementation and download sample application to test http://www.awasthiashish.com/2014/08/uploading-and-downloading-files-from.html
在这里你可以阅读完整的实现并下载示例应用程序来测试 http://www.awasthiashish.com/2014/08/uploading-and-downloading-files-from.html
Full disclosure on the last link above and its contents: I wrote it and it is my TLD.
上面最后一个链接及其内容的完整披露：我写的，它是我的顶级域名。
回答by 32U
Your inputFile should look something like the following where gciuiCheckin is a reference to the backing bean. In this case the inputFile control is in a jsff contained as a region inside a jspx with usesUpload="true", but this would be similar if you are putting your controls directly in the jspx, the main thing is you need to bind the control value to a backing bean variable of type UploadedFile:
您的 inputFile 应该类似于以下内容，其中 gciuiCheckin 是对支持 bean 的引用。在这种情况下，inputFile 控件位于一个 jsff 中，作为一个区域包含在一个带有 usesUpload="true" 的 jspx 中，但是如果您将控件直接放在 jspx 中，这将是类似的，主要是您需要绑定控件类型为 UploadedFile 的支持 bean 变量的值：
<af:inputFile label=" " id="ifDoc" columns="50"
value="#{pageFlowScope.gciuiCheckin.filesToUpload}"
maximumFiles="#{pageFlowScope.gciuiCheckin.maxFilesCanBeUploaded}"
autoHeightRows="0" rows="5" uploadType="auto"/>
Then you also should have a commandButton to call a bean method once user has selected the file (each file typically is uploaded to server as the user selects or drag drops each one):
然后，您还应该有一个 commandButton 来在用户选择文件后调用 bean 方法（每个文件通常在用户选择或拖放每个文件时上传到服务器）：
<af:commandButton text="Commit File(s)" id="cbUpload"
partialSubmit="true" action="#{pageFlowScope.gciuiCheckin.saveUploadedFilesAction}"/>
You will need this import in the backing bean:
您将需要在支持 bean 中进行此导入：
import org.apache.myfaces.trinidad.model.UploadedFile;
In the backing bean, create a List with accessors to hold the uploaded files:
在支持 bean 中，创建一个带有访问器的 List 来保存上传的文件：
private List<UploadedFile> filesToUpload;
In the method called by the commandButton, you will do something like:
在 commandButton 调用的方法中，您将执行以下操作：
public String saveUploadedFilesAction() {
List<UploadedFile> files = this.getFilesToUpload();
if (files == null || files.size() == 0) {
displayMessageToUser(FacesMessage.SEVERITY_WARN, checkinErrorMessage);
return null;
}
//iterate each file and check size, extension, etc...
for (int i = 0; i < files.size(); i++) {
UploadedFile currFile = files.get(i);
//now do something with the file...
}
...
Hope this helps.
希望这可以帮助。
