javascript 正则表达式匹配具有两个或多个特殊字符的强密码
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Regex match a strong password with two or more special characters
提问by rwyland
I need to regex match a password field using javascript with the following requirements:
我需要使用具有以下要求的 javascript 正则表达式匹配密码字段：
- At least 15 characters
- two or more lower case letters
- two or more upper case letters
- two or more digits
- two or more of the following special characters: !@#$%^&*-
- 至少 15 个字符
- 两个或更多小写字母
- 两个或多个大写字母
- 两位或更多位数字
- 两个或多个以下特殊字符：!@#$%^&*-
I have a regex that takes care of MOST cases:
我有一个处理大多数情况的正则表达式：
/^.*(?=.{15,})(?=.{2,}\d)(?=.{2,}[a-z])(?=.{2,}[A-Z])(?=.{2,}[\!\@\#$\%\^\&\*\-]).*$/
The problem here is with the symbols, it works with:
这里的问题在于符号，它适用于：
P@ssw0rdP@ssw0rd Pssw0rdPssw0rd@@ Pssw0rd@@Pssw0rd
P@ssw0rdP@ssw0rd Pssw0rdPssw0rd@@ Pssw0rd@@Pssw0rd
But not:
但不是：
@@Pssw0rdPssw0rd
@@Pssw0rdPssw0rd
I have a random password generator set up to exhaustively test this, so any ideas are greatly appreciated. Thanks!
我设置了一个随机密码生成器来详尽地测试这个，所以非常感谢任何想法。谢谢！
回答by kennytm
/^(?=(?:.*[a-z]){2})(?=(?:.*[A-Z]){2})(?=(?:.*\d){2})(?=(?:.*[!@#$%^&*-]){2}).{15,}$/
Your lookaheads are wrong. The pattern
你的前瞻是错误的。图案
(?=.{2,}[class])
means to match 2 or more characters (no matter what characters), then followed by 1 character of the desired class. This is entirely different from "2 or more character of the desired class" you specified.
表示匹配 2 个或更多字符（无论是什么字符），然后是所需类的 1 个字符。这与您指定的“所需类别的 2 个或多个字符”完全不同。
To correctly test if a character of desired class is in the text, use
要正确测试文本中是否存在所需类别的字符，请使用
(?=.*[class])
and since you want to check it twice, repeat the pattern
并且由于您想检查两次，请重复该模式
(?=.*[class].*[class])
# equivalent to (?=(?:.*[class]){2})
回答by Martin Jespersen
I'm not sure a single regexp is the way to go for this test.
我不确定单个正则表达式是否适合进行此测试。
Personally i'd implement it something like this: (treat as pseudo code, i haven't tested it)
我个人会像这样实现它：（视为伪代码，我还没有测试过）
function testPassword(pw) {
var len = pw.length;
if(len < 15) return false;
if(pw.replace(/[a-z]/,'').length > len - 2) return false;
if(pw.replace(/[A-Z]/,'').length > len - 2) return false;
if(pw.replace(/[0-9]/,'').length > len - 2) return false;
if(pw.replace(/[!@#$%^&*-]/,'').length > len - 2) return false;
return true;
}
回答by Martin Jespersen
There are some good explanations already, so I'm just piling on ...
已经有一些很好的解释，所以我只是在堆积......
/^(?= .{15} )(?= (?:.*[[:lower:]]){2} )(?= (?:.*[[:upper:]]){2} )(?= (?:.*[[:digit:]]){2} )(?= (?:.*[!@#$%^&*-]){2} )/x
/^(?= .{15} )(?= (?:.*[[:lower:]]){2} )(?= (?:.*[[:upper:]]){2} )(?= (?:.*[[:digit:]]){2} )(?= (?:.*[!@#$%^&*-]){2} )/x
