使用 will_paginate 在 Ruby 中对数组进行分页
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Paginating an Array in Ruby with will_paginate
提问by Pi Horse
I have an array @level1 which looks like this :
我有一个数组@level1，它看起来像这样：
[[3.0, 4, 2], [2.0, 48, 3], [2.1, 56, 4], ............]
I want to apply pagination on this array such each page displays only a few rows at once. I tried this:
我想在这个数组上应用分页，这样每个页面一次只显示几行。我试过这个：
@temp1 = @level1.paginate(:page => params[:page])
But it throws the following error:
但它抛出以下错误：
undefined method `paginate' for [[3.0, 4, 2], [2.0, 48, 3], [2.1, 56, 4]]:Array
How can I perform pagination on this using will_paginate?
如何使用 will_paginate 对此执行分页？
采纳答案by Chris Heald
Sure, you can use WillPaginate::Collectionto construct arbitrary pagination across collections. Assuming an array called values:
当然，您可以使用WillPaginate::Collection跨集合构建任意分页。假设一个名为 的数组values：
@values = WillPaginate::Collection.create(current_page, per_page, values.length) do |pager|
pager.replace values
end
You can then treat @valuesjust like any other WillPaginate collection, including passing it to the will_paginateview helper.
然后，您可以@values像对待任何其他 WillPaginate 集合一样进行处理，包括将其传递给will_paginate视图助手。
回答by Philip Hallstrom
See https://github.com/mislav/will_paginate/blob/master/lib/will_paginate/array.rb
见https://github.com/mislav/will_paginate/blob/master/lib/will_paginate/array.rb
Just require 'will_paginate/array'before you try it and it will work just fine. If it were me, I'd put that in say config/initalizers/will_paginate_extensions.rbso it's available right away and from everywhere.
就require 'will_paginate/array'在你尝试之前，它会工作得很好。如果是我，我会说出来，config/initalizers/will_paginate_extensions.rb这样它就可以立即从任何地方获得。
回答by Francisco Quintero
Given a collectionarray in a Rails project
给定collection一个 Rails 项目中的数组
will_paginate ~>3.0.5
collection.paginate(page: params[:page], per_page: 10)
returns the pagination for the array values.
返回数组值的分页。
Do not forget require 'will_paginate/array'on top of the controller.
不要忘记require 'will_paginate/array'在控制器的顶部。
回答by Alberto Camargo
This is my example based in the answer of @chris-heald
这是我基于@chris-heald 的回答的示例
products = %w(i love ruby on rails)
@products = WillPaginate::Collection.create(params[:page], params[:per_page], products.length) do |pager|
pager.replace products[pager.offset, pager.per_page]
end
回答by Jeremie Ges
I wasn't really happy with the answers provided in this thread.
我对这个线程中提供的答案并不满意。
I came up with this solution.
我想出了这个解决方案。
# app/lib/paged_array.rb
require 'will_paginate/array'
class PagedArray
delegate_missing_to :@paged_collection
def initialize(collection, page: 1, per_page: 20)
@paged_collection = collection.paginate(
page: page,
per_page: per_page
)
end
end
And you can use it like that:
你可以这样使用它：
superheroes = %w[spiderman batman superman ironman]
PagedArray.new(superheroes, page: 1, per_page: 2)
I like this solution since it's explicit and you are not polluting your standard classes.
我喜欢这个解决方案，因为它是明确的，而且你不会污染你的标准类。
That being said, you are dependent of rails since I use "delegate_missing_to".
话虽如此，因为我使用“delegate_missing_to”，所以您依赖于 rails。
