java Java正则表达式删除所有尾随数字？
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Java regex to remove all trailing numbers?
提问by brandon k
I want to remove any numbers from the end of a string, for example:
我想从字符串的末尾删除任何数字，例如：
"TestUser12324" -> "TestUser"
"User2Allow555" -> "User2Allow"
"AnotherUser" -> "AnotherUser"
"Test123" -> "Test"
etc.
等等。
Anyone know how to do this with a regular expression in Java?
有谁知道如何用 Java 中的正则表达式来做到这一点？
回答by brandon k
This should work for the Java String class, where myString contains the username:
这应该适用于 Java String 类，其中 myString 包含用户名：
myString = myString.replaceAll("\d*$", "");
This should match any number of trailing digit characters (0-9) that come at the end of the string and replace them with an empty string.
这应该匹配出现在字符串末尾的任意数量的尾随数字字符 (0-9)，并将它们替换为空字符串。
.
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回答by Devon_C_Miller
Assuming the value is in a string, s:
假设值在一个字符串中，s：
s = s.replaceAll("[0-9]*$", "");
回答by Danijel Mandi?
This should be the correct expression:
这应该是正确的表达：
(.+[^0-9])\d*$
