java 从原始资源文本文件中读取
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Reading from a raw resource text file
提问by John
I'm trying to keep a .txt file in my res\raw file in Android Studio and read/parse the file. I have a file "my_file.txt" in a folder called "raw" that I created in the "res" directory (that I didn't create).
我试图在 Android Studio 的 res\raw 文件中保留一个 .txt 文件并读取/解析该文件。我在“res”目录(不是我创建的)中创建的名为“raw”的文件夹中有一个文件“my_file.txt”。
Here's what I think my main issue is: When creating the File object (to use with the Scanner object), what path should I pass in for my text file?
我认为我的主要问题是:创建 File 对象(与 Scanner 对象一起使用)时,我应该为文本文件传入什么路径?
Here's my code:
这是我的代码:
private void readFile(){
Scanner scanner = null;
try {
scanner = new Scanner(new File("\res\raw\my_file.txt")); //I've also tried without the .txt extension
Log.v("readFile->try","Trying to read file.");
}catch(Exception e)
{
//Send error message.
}
if(scanner != null) {
while (scanner.hasNext()) {
String[] line = scanner.nextLine().split("\t");
//Process string here
}
}
}
回答by Woodi_333
Think you are looking for something along the lines of
认为你正在寻找类似的东西
InputStream is = ctx.getResources().openRawResource(res_id);
Where ctx is a instance of Context
其中 ctx 是 Context 的一个实例
回答by Panther
I suggest you put it in assets
folder under the src/main
folder. Then you can use the getAssets
method to retrieve the file like this
我建议你把它放在assets
文件夹下的src/main
文件夹中。然后你可以使用该getAssets
方法来检索这样的文件
InputStream in = (Activity)getContext().getAssets().open("my_file.txt")
If the folder does not exists, create one :-/
如果该文件夹不存在,请创建一个:-/
回答by Sayed Muhammad Idrees
or You can use this Function
或者您可以使用此功能
private String readFile()
{
String myData = "";
File myExternalFile = new File("assets/","log.txt");
try {
FileInputStream fis = new FileInputStream(myExternalFile);
DataInputStream in = new DataInputStream(fis);
BufferedReader br = new BufferedReader(new InputStreamReader(in));
String strLine;
while ((strLine = br.readLine()) != null) {
myData = myData + strLine + "\n";
}
br.close();
in.close();
fis.close();
} catch (IOException e)
{
e.printStackTrace();
}
return myData;
}
just past in the path Location.
刚刚过去的路径位置。