Java 不可比数据类型 char 和 String
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Java Incomparable Data types char and String
提问by Nate
When I run the Javac, it tells me that i have an incomparable data types char and String in the
当我运行 Javac 时，它告诉我我有一个无与伦比的数据类型 char 和 String
while(responseChar == "y")
not sure what to change to fix this error
不确定要更改什么来修复此错误
import java.util.Scanner;
public class UseOrder
{
public static void main(String[] args)
{
int answer, num, q;
String name, response;
double p;
char responseChar;
Scanner keyboard = new Scanner(System.in);
Order order1 = new Order();
order1.setCustomerName();
order1.setCustomerNum();
order1.setQuantity();
order1.setUnitPrice();
order1.computePrice();
order1.displayInfo();
keyboard.nextLine();
System.out.println("Do you need the shipping and handling service?");
System.out.println("Enter y or n :");
response = keyboard.nextLine();
responseChar = response.charAt(0);
while(responseChar == "y")
{
ShippedOrder order2 = new ShippedOrder();
order2.getCustomerName();
order2.getCustomerNum();
order2.getQuantity();
order2.getUnitPrice();
order2.computePrice();
order2.displayInfo();
}
}
}
回答by Jeffrey
To define a character literal, use a single quote: '. Double quotes define string literals.
要定义字符文字，请使用单引号：'。双引号定义字符串文字。
while(responseChar == 'y')
回答by Hunter McMillen
Optionally you could use the big C Characterclass to convert your charto a String:
或者，您可以使用 big CCharacter类将您的转换char为String：
String converted = Character.toString(responseChar);
while(converted.equalsIgnoreCase("y"))
{
// ...
}
But this version is much more verbose than the literal comparison suggested by Jeffrey
但是这个版本比杰弗里建议的字面比较要冗长得多
回答by Amit Deshpande
Instead of "y"do this 'y'. ""Represents string.
而不是"y"这样做'y'。 ""代表字符串。
