Java JSON 类型不匹配或 org.json.jsonecxeption
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JSON type mismatch or org.json.jsonecxeption
提问by Vivek Warde
The link is http://iipacademy.in/askpoll/ten_feed.php
链接是 http://iipacademy.in/askpoll/ten_feed.php
exception is in onPostExecute() method (4th line) :
异常在 onPostExecute() 方法（第 4 行）中：
Log.i("result", result);
try {
if (result != null) {
JSONArray jsonArray = new JSONArray(result); // erreor
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject objJson = jsonArray.getJSONObject(i);
TopTenGetterSetter obj = new TopTenGetterSetter();
obj.setQ(objJson.getString("question"));
obj.setA(objJson.getString("option1"));
obj.setB(objJson.getString("option2"));
obj.setC(objJson.getString("option3"));
obj.setD(objJson.getString("option4"));
polls.add(obj);
}
}
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "error",
Toast.LENGTH_SHORT).show();
}
LOGCAT:
逻辑猫：
12-18 03:20:45.447: W/System.err(2790): org.json.JSONException: Value response of type java.lang.String cannot be converted to JSONArray
12-18 03:20:45.447: W/System.err(2790): at org.json.JSON.typeMismatch(JSON.java:111)
12-18 03:20:45.447: W/System.err(2790): at org.json.JSONArray.<init>(JSONArray.java:91)
12-18 03:20:45.447: W/System.err(2790): at org.json.JSONArray.<init>(JSONArray.java:103)
12-18 03:20:45.447: W/System.err(2790): at com.example.askpollie.LatestPollParticipated$FetchingEventsDetails.onPostExecute(LatestPollParticipated.java:188)
12-18 03:20:45.447: W/System.err(2790): at com.example.askpollie.LatestPollParticipated$FetchingEventsDetails.onPostExecute(LatestPollParticipated.java:1)
12-18 03:20:45.447: W/System.err(2790): at android.os.AsyncTask.finish(AsyncTask.java:631)
12-18 03:20:45.447: W/System.err(2790): at android.os.AsyncTask.access0(AsyncTask.java:177)
12-18 03:20:45.447: W/System.err(2790): at android.os.AsyncTask$InternalHandler.handleMessage(AsyncTask.java:644)
12-18 03:20:45.447: W/System.err(2790): at android.os.Handler.dispatchMessage(Handler.java:99)
12-18 03:20:45.447: W/System.err(2790): at android.os.Looper.loop(Looper.java:137)
12-18 03:20:45.447: W/System.err(2790): at android.app.ActivityThread.main(ActivityThread.java:5103)
12-18 03:20:45.447: W/System.err(2790): at java.lang.reflect.Method.invokeNative(Native Method)
12-18 03:20:45.447: W/System.err(2790): at java.lang.reflect.Method.invoke(Method.java:525)
12-18 03:20:45.447: W/System.err(2790): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:737)
12-18 03:20:45.447: W/System.err(2790): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:553)
12-18 03:20:45.447: W/System.err(2790): at dalvik.system.NativeStart.main(Native Method)
12-18 03:20:45.447: D/dalvikvm(2790): GC_FOR_ALLOC freed 5131K, 55% free 4437K/9672K, paused 2ms, total 2ms
Message is an array so what should be its code or how to can it be solved ?
消息是一个数组，那么它的代码应该是什么或者如何解决？
Thanks in advance . . .
提前致谢 。. .
采纳答案by Raghunandan
org.json.JSONException: Value response of type java.lang.String cannot be converted to JSONArray
Looks like response is a string not a json array
看起来响应是一个字符串而不是一个 json 数组
{ // json object node
"response": { // json object response
"result": 1,
"Message": [ // json array Message
{ // json object node
"pollid": "98",
"category": "Entertainment",
"question": "what", // string
"option1": "981.mov",
The result is a json object not json array
结果是一个json对象而不是json数组
JSONArray jsonArray = new JSONArray(result);
Should be
应该
JSONObject jObj = new JSONObject(result);
JSONObject response = jObj.getJSONObject("response");
//JSONObject jb = new JSONObject(response);
JSONArray jr = response.getJSONArray("Message");
for(int i=0;i<jr.length();i++)
{
JSONObject jb1 = jr.getJSONObject(i);
String question = jb1.getString("question");
Log.i(".......",question);
}
回答by stefana
Result is not an array, Message is.
结果不是数组，消息是。
回答by Mario Stoilov
Value response of type java.lang.String cannot be converted to JSONArray
You are trying to convert a single object into an array.
您正在尝试将单个对象转换为数组。
回答by Damien R.
Try this:
尝试这个：
Log.i("result", result);
try {
if (result != null) {
JSONObject jObject = new JSONObject(result);
JSONArray jsonArray = jObject.getJSONObject("response").getJSONArray("Message");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject objJson = jsonArray.getJSONObject(i);
TopTenGetterSetter obj = new TopTenGetterSetter();
/*
* [{"job_id":"1","job_staff_id":"","job_name":"Account",
* "job_detail":"test\r\ntesds","job_start_date":
* "2013-11-08"
* ,"job_end_date":"2013-11-10","job_amount":"500"
* ,"job_progress":"","job_complete_status":"0"}]
*/
obj.setQ(objJson.getString("question"));
obj.setA(objJson.getString("option1"));
obj.setB(objJson.getString("option2"));
obj.setC(objJson.getString("option3"));
obj.setD(objJson.getString("option4"));
polls.add(obj);
// am = Customer.info.get(pos).getJamount();
// Toast.makeText(getApplicationContext(), am + result,
// Toast.LENGTH_LONG).show();
}
}
} catch (JSONException e) {
e.printStackTrace();
Toast.makeText(getApplicationContext(), "error",
Toast.LENGTH_SHORT).show();
}
As mario and nfear said, you are trying to cast a JSONObject into a JSONArray.
正如 mario 和 nfear 所说，您正在尝试将 JSONObject 转换为 JSONArray。
回答by ρяσ?ρ?я K
String content JSONObject as root element instead of JSONArray.to get MessageJSONArray from String you should first get responseJSONObject then get MessageJSONArray as:
字符串内容 JSONObject 作为根元素而不是MessageJSONArray。要从 String获取JSONArray，您应该首先获取responseJSONObject 然后获取MessageJSONArray 为：
JSONObject jsonobj = new JSONObject(result);
// get response JSONObject
JSONObject jsonobj_response = jsonobj.getJSONObject("response");
// get Message JSONArray from jsonobj_response
JSONArray jsonArray = jsonobj_response.getJSONArray("Message");
// your code here.....
回答by SathishKumar
Try this,
尝试这个，
try {
if (result != null) {
JSONArray jsonArray = new JSONObject(result).getJSONObject("response").getJSONArray("Message");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject objJson = jsonArray.getJSONObject(i);
TopTenGetterSetter obj = new TopTenGetterSetter();
/*
* [{"job_id":"1","job_staff_id":"","job_name":"Account",
* "job_detail":"test\r\ntesds","job_start_date":
* "2013-11-08"
* ,"job_end_date":"2013-11-10","job_amount":"500"
* ,"job_progress":"","job_complete_status":"0"}]
*/
obj.setQ(objJson.getString("question"));
obj.setA(objJson.getString("option1"));
obj.setB(objJson.getString("option2"));
obj.setC(objJson.getString("option3"));
obj.setD(objJson.getString("option4"));
polls.add(obj);
// am = Customer.info.get(pos).getJamount();
// Toast.makeText(getApplicationContext(), am + result,
// Toast.LENGTH_LONG).show();
}
}
}
回答by Dinesh Prajapati
better to use GSON library instead of parsing it manually. GSON you can find it on goggling. and sample examples are given with that.
最好使用 GSON 库而不是手动解析它。GSON 你可以在 goggling 上找到它。并给出了示例示例。
回答by pyus13
The JSON you have posted is having
您发布的 JSON 具有
// Key "response" , Value type JsonObject
JSONObject jsonObject=jsonObjectOfRsponse.getJsonObject(key);
//Key "Message" , Value type Json Array
JSONArray jsonArray=jsonObject.getJsonArray(key);
After getting the jsonArray, use this in a loop to parse the Json according to the type of value inside it.
得到jsonArray后，循环使用this，根据里面的值类型解析Json。
So check if you are parsing the json according to the type of value it is holding.
因此，请检查您是否根据其持有的值类型解析 json。
