java 在java中过滤字符串
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Filtering string in java
提问by regeme
It's not about filtering bad words so get in. Imagine that you have list of strings named as abcd,abcde,abcdef,abfg,abdc if a user gives string abc as filter in ConsoleProgram abcd,abcde and abcdef will be printed out. I thought about using substring but I couldn't achieved it does anybody have any idea .. note that I am new to java and not competent thanks!
这不是关于过滤坏词所以进入。想象一下，如果用户在 ConsoleProgram 中提供字符串 abc 作为过滤器 abcd，abcde 和 abcdef 将被打印出来，那么你有一个名为 abcd,abcde,abcdef,abfg,abdc 的字符串列表。我想过使用子字符串，但我无法实现它是否有人有任何想法..请注意，我是 Java 新手，不胜任，谢谢！
回答by alvarodev
The first thing you need is learn about String Regex, maybe here: http://docs.oracle.com/javase/tutorial/essential/regex/. Try out the next simply code.
您需要的第一件事是了解 String Regex，可能在这里：http: //docs.oracle.com/javase/tutorial/essential/regex/。尝试下一个简单的代码。
public class StringMatcher {
public static void main(String[] args) {
String[] words = new String[]{"abcd", "abcde", "abcdef", "abfg", "abdc"};
String filter = "abc";
for (String word : words) {
if (word.matches(filter + "(.*)")) {
System.out.println("This pass the filter: " + word);
}
}
}
}
回答by Achintya Jha
Try this: If the item in list contains the string inputted by user it will get printed.
试试这个：如果列表中的项目包含用户输入的字符串，它将被打印出来。
input = "abc";
for(int i = 0 ; i < list.size(); i++){
if (list.get(i).contains(input))
System.out.println(list.get(i));
}
回答by Joel Christophel
Let's say your Strings are in an ArrayList called wordBank.
假设您的字符串位于名为 wordBank 的 ArrayList 中。
for(String i : wordBank) { //loops through the array with 'i' being current index
if(i.contains("abc")) { //checks if index contains filter String
System.out.println(i); //prints out index if filter String is present
}
}
回答by Milo? Luka?ka
use String.contains()- it returns true when string contains given char sequence, see string-javadoc
使用String.contains()- 当字符串包含给定的字符序列时返回 true，请参阅string-javadoc
