javascript 如何在 window.location.search 中搜索特定文本？
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How can I search window.location.search for specific text?
提问by Samuel Bala
I have the following code and I want it to show the div only when the part after the "?" includes "gclid=". Note the url could look like xxxxxx.com/?gclid=kljl3j4lk3j4l23
我有以下代码，我希望它仅在“？”之后的部分显示 div。包括“gclid=”。注意 url 可能看起来像 xxxxxx.com/?gclid=kljl3j4lk3j4l23
I am not quite sure how to incorporate a partial string search so it only looks for "?gclid"
我不太确定如何合并部分字符串搜索，因此它只查找“？gclid”
<script type="text/javascript">
$(function(){
if (window.location.search == "?gclid") {
$('#new').show();
} else {
$('#new').hide();
}
});
</script>
I am a bit new to this so pardon my ignorance
我对此有点陌生所以请原谅我的无知
回答by Gabe
You could use indexOf()
你可以用 indexOf()
if(window.location.search.indexOf("gclid=") > -1)
回答by Jo So
if (window.location.search.match(/[?&]gclid=/))
回答by Vinod Srivastav
You can use javaScript splitto do that
您可以使用 javaScript split来做到这一点
Suppose you have a url like
假设你有一个像
//the url
var path = "http://www.website.com/profile?var1=abc&var2=def&var3=ghi";
//get all url parameters
var parameters = path.split("?")[1];
// get the parameters
var para1 = parameters.split("&")[0];
var para2 = parameters.split("&")[1];
var para3 = parameters.split("&")[2];
// get the parameter value
var para1var = para1.split("=")[1];
var para2var = para2.split("=")[1];
var para3var = para3.split("=")[1];回答by hoogw
Extract each parameter one by one, working code:
一一提取每个参数，工作代码：
http://localhost:10/mapserver1/viewer/?config=viewer_simple1&url=https://maps2.dcgis.dc.gov/dcgis/rest/services/Zoning/MapServer&zoom=17&lat=38.917292&long=-77.036420
You could do:
你可以这样做：
var ___zoom;
var ___lat;
var ___long;
var ___basemap;
var ___type;
var ___url;
var ___title;
var ___opacity;
/*
* if (value) {
*
* }
*
* will evaluate to true if value is not:
null
undefined
NaN
empty string ("")
false
0
*
*
*
*/
if ( location.search.match(/zoom=([^&]*)/i) )
{
___zoom = location.search.match(/zoom=([^&]*)/i)[1];
}
if ( location.search.match(/lat=([^&]*)/i) )
{
___lat = location.search.match(/lat=([^&]*)/i)[1];
}
if (location.search.match(/long=([^&]*)/i))
{
___long = location.search.match(/long=([^&]*)/i)[1];
}
if (location.search.match(/basemap=([^&]*)/i))
{
___basemap = location.search.match(/basemap=([^&]*)/i)[1];
}
if (location.search.match(/type=([^&]*)/i))
{
___type = location.search.match(/type=([^&]*)/i)[1];
}
if (location.search.match(/url=([^&]*)/i))
{
___url = location.search.match(/url=([^&]*)/i)[1];
}
if (location.search.match(/title=([^&]*)/i))
{
___title = location.search.match(/title=([^&]*)/i)[1];
}
if (location.search.match(/opacity=([^&]*)/i))
{
___opacity = location.search.match(/opacity=([^&]*)/i)[1];
}
//console.log(location.search.match(/zoom=([^&]*)/i)[0]); // 'zoom=17'
//console.log(location.search.match(/zoom=([^&]*)/i)[1]); // '17'
console.log(___zoom);
console.log(___lat);
console.log(___long);
console.log(___basemap);
console.log(___type);
console.log(___url);
console.log(___title);
console.log(___opacity);
回答by Jarrett Meyer
You can do this either with a Regular Expression or substring and text parsing.
您可以使用正则表达式或子字符串和文本解析来执行此操作。
var stringPart = window.location.search.substr(0, 6);
if (stringPart == "?gclid") { ...
or
或者
var re = new RegExp(/^\?gclid/);
if (window.location.search.match(re)) { ...
Both of those should get you there.
这两个都应该让你到达那里。
