spring 从类路径加载文件
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loading a file from classpath
提问by Steer360
I have a line of code that is : File file = new File(getFile())in a java class HandleData.java
我有一行代码：File file = new File(getFile())在 java 类中HandleData.java
Method - getFile()takes the value of the property fileName. And fileNameis injected through application_context.xmlwith a bean section of the class - HandleData as below:
方法 -getFile()获取属性的值fileName。并fileName通过application_context.xml类的 bean 部分注入 - HandleData 如下：
<bean id="dataHandler" class="com.profile.transaction.HandleData">
<property name="fileName" value="DataFile.xml"></property>
</bean>
I build the project successfully and checked that - DataFile.xmlis present in WEB-INF/classes. And the HandleData.class is present in WEB-INF/classes/com/profile/transacon
我成功构建了项目并检查了 -DataFile.xml是否存在于WEB-INF/classes. 并且 HandleData.class 存在于WEB-INF/classes/com/profile/transacon
But when I run it it throws me filenotfound exception.
If I inject the absolute path (C:\MyProjectWorkspace\DataProject\target\ProfileService\WEB-INF\classes\DataFile.xmlit finds the file successfully.).
但是当我运行它时，它会抛出 filenotfound 异常。如果我注入绝对路径（C:\MyProjectWorkspace\DataProject\target\ProfileService\WEB-INF\classes\DataFile.xml它成功找到文件。）。
Could someone help in figuring out the proper path to be injected so that the file is taken from the classpath ?
有人可以帮助找出要注入的正确路径，以便从类路径中获取文件吗？
回答by helmy
While injecting a Fileis generally the preferred approach, you can also leverage Spring's ResourceLoader for dynamic loading of resources.
虽然注入 aFile通常是首选方法，但您也可以利用 Spring 的 ResourceLoader 来动态加载资源。
Generally this is as simple as injecting the ResourceLoaderinto your Spring bean:
通常，这就像将 注入ResourceLoader到您的 Spring bean 中一样简单：
@Autowired
private ResourceLoader resourceLoader;
Then to load from the classpath:
然后从类路径加载：
resourceLoader.getResource("classpath:myfile.txt");
回答by Lucas
You should have:
你应该有：
<property name="fileName" value="classpath:DataFile.xml" />
And it should be injected as a org.springframework.core.io.Resourcesimilar to this answer
它应该被注入的org.springframework.core.io.Resource类似这样的回答
回答by Sudhakar
Since OP is injecting Only the fileName through spring, still want to create the File Object through code , You should Use ClassLoadeer to read the file
由于OP是通过spring只注入文件名，还是想通过代码创建文件对象，你应该使用ClassLoadeer来读取文件
Try this
尝试这个
InputStream is = HandleData.class.getClassLoader().getResourceAsStream(getFile()));
Edit
编辑
Heres the remainder of code , to read the file
下面是代码的其余部分，用于读取文件
BufferedInputStream bf = new BufferedInputStream(is);
DataInputStream dis = new DataInputStream(bf);
while (dis.available() != 0) {
System.out.println(dis.readLine());
}
Edit 2
编辑 2
Since you want it as File Object, to get hold of the FileInputStream
既然你想把它作为文件对象，就可以得到 FileInputStream
try this
尝试这个
FileInputStream fisTargetFile = new FileInputStream(new File(HandleData.class.getClassLoader().getResource(getFile()).getFile()));
