Typescript / Angular2:将 JSON 转换为与 Observable 和 JSONP 的接口
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/37212948/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Typescript / Angular2: Cast JSON to interface with Observable & JSONP
提问by safari
I'd like to cast my json-array to my interface which I've created and like to display it in the browser. I think there is probably something wrong with my interface but I can't figure it out... What do I need to change to get my code running?
我想将我的 json-array 投射到我创建的界面并希望在浏览器中显示它。我认为我的界面可能有问题,但我无法弄清楚......我需要更改什么才能运行我的代码?
Interface:
界面:
export interface Video {
id: number;
name: string;
description: string;
createdAt: string;
}
app.ts
应用程序
import {JSONP_PROVIDERS, Jsonp} from '@angular/http';
import {Observable} from '../../../node_modules/rxjs';
import 'rxjs/add/operator/map';
import 'rxjs/add/operator/share';
import {Video} from './networking/api';
private videoData: Observable<Video[]>;
ngOnInit() {
this.displayNewstVideo(10);
}
private displayNewstVideo(count: number) {
this.videoData = this.jsonp
.get('localhost:8080/video/newst/' + count + '?jsonp=JSONP_CALLBACK')
.map(res => (res.json() as Video[]));
alert(this.videoData.count);
}
app.html
应用程序.html
<div class="container">
<div class="video" style="font-family:sans-serif" *ngFor="#entry of videoData | async; #i = index">
<br *ngIf="i > 0" />
<span class="title" style="font-size:1.2rem">
<span>{{i + 1}}. </span>
<a href={{entry.urlDesktop}}>{{entry.name}}</a>
</span>
<span> ({{entry.description}})</span>
<div>Submitted at {{entry.createdAt * 1000 | date:"mediumTime"}}.</div>
</div>
JSON
JSON
[{
id: 1,
name: "Some Name",
description: "BlaBla",
createdAt: "2016-05-04 13:30:01.0",
},
{
id: 2,
name: "Some Name",
description: "BlaBla",
createdAt: "2016-05-04 13:30:01.0",
}]
Edits
编辑
- I've checked if the request is correct in my network-tab in chrome and it is working as excepted: 200 OK --> Response ist also fine
- I edited my code as Thierry stated out and now it is finally showing the first object in my array :-)!! But I get following error now:
- 我已经检查了 chrome 网络选项卡中的请求是否正确,并且它正常工作:200 OK --> 响应也很好
- 我按照蒂埃里所说的那样编辑了我的代码,现在它终于显示了我数组中的第一个对象:-)!!但我现在收到以下错误:
Uncaught EXCEPTION: Error in app/html/app.html:27:11 ORIGINAL EXCEPTION: RangeError: Provided date is not in valid range. ORIGINAL STACKTRACE: RangeError: Provided date is not in valid range. at boundformat(native) at Function.DateFormatter.format (http://localhost:3000/node_modules/@angular/common/src/facade/intl.js:100:26) at DatePipe.transform (http://localhost:3000/node_modules/@angular/common/src/pipes/date_pipe.js:25:37) at eval (http://localhost:3000/node_modules/@angular/core/src/linker/view_utils.js:188:22) at DebugAppView._View_AppComponent1.detectChangesInternal (AppComponent.template.js:377:148) at DebugAppView.AppView.detectChanges (http://localhost:3000/node_modules/@angular/core/src/linker/view.js:200:14) at DebugAppView.detectChanges (http://localhost:3000/node_modules/@angular/core/src/linker/view.js:289:44) at DebugAppView.AppView.detectContentChildrenChanges (http://localhost:3000/node_modules/@angular/core/src/linker/view.js:215:37) at DebugAppView._View_AppComponent0.detectChangesInternal (AppComponent.template.js:198:8) at DebugAppView.AppView.detectChanges (http://localhost:3000/node_modules/@angular/core/src/linker/view.js:200:14) ERROR CONTEXT: [object Object]
Uncaught EXCEPTION: Error in app/html/app.html:27:11 ORIGINAL EXCEPTION: RangeError: 提供的日期不在有效范围内。原始堆栈跟踪:范围错误:提供的日期不在有效范围内。在boundformat在Function.DateFormatter.format((天然)的http://本地主机:3000/node_modules/@angular/common/src/facade/intl.js:100:26)在DatePipe.transform(HTTP://本地主机: 3000/node_modules/@angular/common/src/pipes/date_pipe.js:25:37) 在 eval ( http://localhost:3000/node_modules/@angular/core/src/linker/view_utils.js:188:22) 在 DebugAppView._View_AppComponent1.detectChangesInternal (AppComponent.template.js:377:148) 在 DebugAppView.AppView.detectChanges (http://localhost:3000/node_modules/@angular/core/src/linker/view.js:200:14) 在 DebugAppView.detectChanges ( http://localhost:3000/node_modules/@angular/core/src/linker /view.js:289:44) 在 DebugAppView.AppView.detectContentChildrenChanges ( http://localhost:3000/node_modules/@angular/core/src/linker/view.js:215:37) 在 DebugAppView._View_AppComponent0.detectChangesInternal ( AppComponent.template.js:198:8) 在 DebugAppView.AppView.detectChanges ( http://localhost:3000/node_modules/@angular/core/src/linker/view.js:200:14) 错误上下文:[object Object ]
采纳答案by Thierry Templier
You could try the following instead:
您可以尝试以下操作:
this.videoData = this.jsonp
.get('localhost:8080/video/newst/' + count +
'?jsonp=JSONP_CALLBACK')
.map(res => <Video[]>res.json();
Edit
编辑
I think that your request doesn't return JSONP content but classical one (JSON). If so, you could try the following:
我认为您的请求不会返回 JSONP 内容,而是返回经典内容 (JSON)。如果是这样,您可以尝试以下操作:
import { bootstrap } from 'angular2/platform/browser';
import { Component } from 'angular2/core';
import { HTTP_PROVIDERS, Http } from 'angular2/http';
import "rxjs/add/operator/map";
@Component({
selector: "app",
templateUrl: "app.html",
providers: [HTTP_PROVIDERS]
})
class App {
private feedData: Observable<Video[]>;
constructor(private http: Http) { }
ngOnInit() {
this.displayNewstVideo(10);
}
private displayNewstVideo(count: number) {
this.videoData = this.http
.get('localhost:8080/video/newst/' + count)
.map(res => (res.json() as Video[]))
.do(videoData => {
console.log(videoData);
});
}
}
bootstrap(App);
回答by wolfhoundjesse
Try using a class instead of an interface, so in this case video.model.ts would be:
尝试使用类而不是接口,所以在这种情况下 video.model.ts 将是:
export class Video {
constructor(
public id: number,
public name: string,
public description: string,
public createdAt: string){}
}
回答by David Pine
I gave a presentation of TypeScriptrecently, this reminded me of what of the slide's titles "There is no interface!" In TypeScriptwhen you define an interface
, it actually compiles down to nothing. Which can be somewhat misleading. I think I understand what you're trying to do though:
我最近做了一个TypeScript的演示,这让我想起了幻灯片的标题“没有界面!” 在TypeScript 中,当您定义 时interface
,它实际上编译为空。这可能有点误导。我想我明白你想要做什么:
The issue is the way that the JSONPobject comes back, it's padded. So it sits in the index [1]
. Try this instead:
问题是JSONP对象返回的方式,它被填充。所以它位于索引中[1]
。试试这个:
this.videoData = this.jsonp
.get('localhost:8080/video/newst/' + count +
'?jsonp=JSONP_CALLBACK')
.map(res => <Video[]>res.json()[1]);