如何在 C++ 中将 std::wstring 转换为 LPCTSTR?
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How to convert std::wstring to LPCTSTR in C++?
提问by Ernestas Gruodis
I have Windows registry key value in wstring
format. Now I want to pass it to this code (first argument - path to javaw.exe):
我有wstring
格式的Windows 注册表项值。现在我想把它传递给这个代码(第一个参数 - javaw.exe 的路径):
std::wstring somePath(L"....\bin\javaw.exe");
if (!CreateProcess("C:\Program Files\Java\jre7\bin\javaw.exe", <--- here should be LPCTSTR, but I have a somePath in wstring format..
cmdline, // Command line.
NULL, // Process handle not inheritable.
NULL, // Thread handle not inheritable.
0, // Set handle inheritance to FALSE.
CREATE_NO_WINDOW, // ON VISTA/WIN7, THIS CREATES NO WINDOW
NULL, // Use parent's environment block.
NULL, // Use parent's starting directory.
&si, // Pointer to STARTUPINFO structure.
&pi)) // Pointer to PROCESS_INFORMATION structure.
{
printf("CreateProcess failed\n");
return 0;
}
How can I do that?
我怎样才能做到这一点?
回答by paulm
Simply use the c_str
function of std::w/string
.
只需使用c_str
的功能std::w/string
。
See here:
看这里:
http://www.cplusplus.com/reference/string/string/c_str/
http://www.cplusplus.com/reference/string/string/c_str/
std::wstring somePath(L"....\bin\javaw.exe");
if (!CreateProcess(somePath.c_str(),
cmdline, // Command line.
NULL, // Process handle not inheritable.
NULL, // Thread handle not inheritable.
0, // Set handle inheritance to FALSE.
CREATE_NO_WINDOW, // ON VISTA/WIN7, THIS CREATES NO WINDOW
NULL, // Use parent's environment block.
NULL, // Use parent's starting directory.
&si, // Pointer to STARTUPINFO structure.
&pi)) // Pointer to PROCESS_INFORMATION structure.
{
printf("CreateProcess failed\n");
return 0;
}
回答by LihO
LPCTSTR
is an old relic. It's a hybrid typedef that either defines char*
if you are using multi-byte strings or wchar_t*
if you are using Unicode. In Visual Studio, this can be changed in general project's settings under "Character Set".
LPCTSTR
是一个古老的遗迹。它是一个混合 typedef,可以定义char*
您是使用多字节字符串还是wchar_t*
使用 Unicode。在 Visual Studio 中,这可以在“字符集”下的常规项目设置中更改。
If you are using Unicode, then:
如果您使用的是 Unicode,则:
std::wstring somePath(L"....\bin\javaw.exe");
LPCTSTR str = somePath.c_str(); // i.e. std::wstring to wchar_t*
If you are using multi-byte, then use this helper:
如果您使用多字节,则使用此帮助程序:
// wide char to multi byte:
std::string ws2s(const std::wstring& wstr)
{
int size_needed = WideCharToMultiByte(CP_ACP, 0, wstr.c_str(), int(wstr.length() + 1), 0, 0, 0, 0);
std::string strTo(size_needed, 0);
WideCharToMultiByte(CP_ACP, 0, wstr.c_str(), int(wstr.length() + 1), &strTo[0], size_needed, 0, 0);
return strTo;
}
i.e. std::wstring
to std::string
that will contain multi-byte string and then to char*
:
即std::wstring
到std::string
将包含多字节字符串,然后到char*
:
LPCTSTR str = ws2s(somePath).c_str();
回答by Ernestas Gruodis
Finally decided to use CreateProcessW as paulm mentioned with a little corrections - values need to be casted (otherwise I get error):
最后决定使用 CreateProcessW 作为 paulm 提到的一些更正 - 需要转换值(否则我会出错):
STARTUPINFOW si;
memset(&si, 0, sizeof (STARTUPINFOW));
si.cb = sizeof (STARTUPINFOW);
si.dwFlags = STARTF_USESHOWWINDOW;
si.wShowWindow = FALSE;
PROCESS_INFORMATION pi;
memset(&pi, 0, sizeof (PROCESS_INFORMATION));
std::wstring cmdline(L" -jar install.jar");
if (!CreateProcessW((LPCWSTR)strKeyValue.c_str(),
(LPWSTR)cmdline.c_str(), // Command line.
NULL, // Process handle not inheritable.
NULL, // Thread handle not inheritable.
0, // Set handle inheritance to FALSE.
CREATE_NO_WINDOW, // ON VISTA/WIN7, THIS CREATES NO WINDOW
NULL, // Use parent's environment block.
NULL, // Use parent's starting directory.
&si, // Pointer to STARTUPINFO structure.
&pi)) // Pointer to PROCESS_INFORMATION structure.
{
printf("CreateProcess failed\n");
return 0;
}
回答by Roi Danton
The safest way when interacting from stdlib classes with TCHAR
s is to use std::basic_string<TCHAR>
and surround raw strings with the TEXT()
macro (since TCHAR
can be narrow and wide depending on project settings).
从 stdlib 类与TCHAR
s交互时最安全的方法是使用宏std::basic_string<TCHAR>
并将原始字符串包围起来TEXT()
(因为TCHAR
根据项目设置可以是窄的和宽的)。
std::basic_string<TCHAR> somePath(TEXT("....\bin\javaw.exe"));
Since you won't win style contests doing this ... another correct method is to use explicitly the narrow or wide version of a WinAPI function. E.g. in that particular case:
由于这样做不会赢得风格竞赛……另一种正确的方法是明确使用 WinAPI 函数的窄版或宽版。例如在那个特殊情况下:
- with
std::string
useCreateProcessA
(which usesLPCSTR
which is a typedef ofchar*
) - with
std::u16string
orstd::wstring
useCreateProcessW
(which usesLPCWSTR
which is a typedef ofwchar_t*
, which is 16-bit in Windows)
- with
std::string
useCreateProcessA
(使用LPCSTR
哪个是 的 typedefchar*
) - with
std::u16string
或std::wstring
useCreateProcessW
(使用LPCWSTR
which 是 的 typedefwchar_t*
,在 Windows 中为 16 位)
In C++17, you could do:
在 C++17 中,你可以这样做:
std::filesystem::path app = "my/path/myprogram.exe";
std::string commandcall = app.filename.string() + " -myAwesomeParams";
// define si, pi
CreateProcessA(
const_cast<LPCSTR>(app.string().c_str()),
const_cast<LPSTR>(commandcall.c_str()),
nullptr, nullptr, false, CREATE_DEFAULT_ERROR_MODE, nullptr, nullptr,
&si, &pi)