从 javascript 字符串中删除 http 或 https

taking off the http or https off a javascript string

提问by Matt Elhotiby

I have the following strings

我有以下字符串

http://example.com
https://example.com
http://www.example.com

how do i get rid of the http://or https://?

我如何摆脱http://或https://？

回答by ncardeli

Try with this:

试试这个：

var url = "https://site.com";
var urlNoProtocol = url.replace(/^https?\:\/\//i, "");

回答by Bick

var txt="https://site.com";
txt=/^http(s)?:\/\/(.+)$/i.exec(txt);
txt=txt[2];

for parsing links without http/https use this:

要解析没有 http/https 的链接，请使用：

var txt="https://site.com";
txt=/^(http(s)?:\/\/)?(.+)$/i.exec(txt);
txt=txt[3];

回答by Vincent D'amour

You can use the URLobject like this:

您可以像这样使用URL对象：

const urlWithoutProtocol = new URL(url).host;

const urlWithoutProtocol = new URL(url).host;

回答by user113716

var str = "https://site.com";

str = str.substr( str.indexOf(':') + 3 );

Instead of .substr(), you could also use .slice()or .substring(). They'll all produce the same result in this situation.

代替.substr()，您也可以使用.slice()或.substring()。在这种情况下，它们都会产生相同的结果。

str = str.slice( str.indexOf(':') + 3 );

str = str.substring( str.indexOf(':') + 3 );

---

---

EDIT:It appears as though the requirements of the question have changed in a comment under another answer.

编辑：似乎问题的要求在另一个答案下的评论中发生了变化。

If there possibly isn'ta http://in the string, then do this:

如果字符串中可能没有a http://，请执行以下操作：

var str = "site.com";

var index = str.indexOf('://');
if( index > -1 )
   str = str.substr( index + 3 );

回答by Green

You may use URL() constructor. It will parse your url string and there will be an entry w/o protocol. So less headache with regexps:

您可以使用URL() 构造函数。它将解析您的 url 字符串，并且会有一个没有协议的条目。所以用正则表达式少头疼：

let u = new URL('https://www.facebook.com/companypage/');
URL {
    hash: ""
    host: "www.facebook.com"
    hostname: "www.facebook.com"
    href: "https://www.facebook.com/companypage/"
    origin: "https://www.facebook.com"
    password: ""
    pathname: "/companypage/"
    port: ""
    protocol: "https:"
    search: ""
    searchParams: URLSearchParams {}
    username: ""
}
u.host // www.facebook.com
u.hostname // www.facebook.com

Although URL()drops out a protocol, it leaves you with wwwpart. In my case I wanted to get rid of that subdomain part as well, so had to use to .replace()anyway.

虽然URL()放弃了协议，但它让你有www一部分。在我的情况下，我也想摆脱那个子域部分，所以.replace()无论如何都必须使用。

u.host.replace(/^www./, '') // www.facebook.com => facebook.com

回答by yowainwright

This answer extends some answers above, http://, https://, or//which is also common.

这个答案扩展了上面的一些答案, http://, https://,或者//这也很常见。

Thanks for answers above that led me to this!

感谢上面的答案让我做到了这一点！

const urls = [ "http://example.com", "https://example.com", "//example.com" ]

// the regex below states: replace `//` or replace `//` and the 'stuff'
const resolveHostNames = urls.map(url => url.replace(/\/\/|.+\/\//, ''))

console.log(resolveHostNames);

Here's a link to a codepen.

这是 codepen的链接。

回答by Rahul

Another efficient solution,

另一个有效的解决方案，

url.replace(/(^(\w+:)?\/\//, '')

url.replace(/(^(\w+:)?\/\//, '')

回答by Evgeny

Strip the protocol from a URL:

从 URL 中剥离协议：

var url = "https://site.com";
var urlNoProto = url.split('/').slice(2).join('/');

Works with any protocol, ftp, http, gopher, nntp, telnet, wais, file, prospero ... all those specified in RFC 1738 with the exception of those without a // in them (mailto, news).

适用于任何协议，ftp、http、gopher、nntp、telnet、wais、file、prospero ... RFC 1738 中指定的所有协议，但其中没有 // 的协议除外（mailto、news）。

回答by UpTheCreek

Assuming there are no double slashes other than the protocol, you could do:

假设除了协议没有双斜线，你可以这样做：

 var url = "https://example.com";
 var noProtocol = url.split('//')[1];

回答by ilyaigpetrov

You may use HTMLHyperlinkElementUtilsof DOM:

你可以使用DOM 的HTMLHyperlinkElementUtils：

function removeProtocol(url) {
  const a = document.createElement('a');
  a.href = url;
  // `url` may be relative, but `a.href` will be absolute.
  return a.href.replace(a.protocol + '//', '');
}

removeProtocol('https://example.com/https://foo');
// 'example.com/https://foo'

removeProtocol('wrong://bad_example/u');
// 'bad_example/u'

From HTMLHyperlinkElementUtils on MDN:

来自MDN 上的 HTMLHyperlinkElementUtils：

a.hostname, example.com
a.host, example.com:3000
a.pathname, /foo/bar.html
a.search, ?a=1&b=2
a.hash, #goo
a.username, a.password, a.port, etc.

a.hostname，example.com
a.host，example.com:3000
a.pathname，/foo/bar.html
a.search，？一个= 1＆B = 2
a.hash，#goo
a.username，a.password，a.port等。