Python 获取 Pandas DataFrame 的行索引值作为列表？
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Get row-index values of Pandas DataFrame as list?
提问by TravisVOX
I'm probably using poor search terms when trying to find this answer. Right now, before indexing a DataFrame, I'm getting a list of values in a column this way...
我在试图找到这个答案时可能使用了糟糕的搜索词。现在，在索引 DataFrame 之前，我以这种方式获取列中的值列表......
list = list(df['column'])
...then I'll set_indexon the column. This seems like a wasted step. When trying the above on an index, I get a key error.
...那我set_index就上专栏了。这似乎是一个浪费的步骤。在索引上尝试上述操作时，出现关键错误。
How can I grab the values in an index (both single and multi) and put them in a list or a list of tuples?
如何获取索引（单个和多个）中的值并将它们放入列表或元组列表中？
采纳答案by Phillip Cloud
To get the indexvalues as a list/listof tuples for Index/MultiIndexdo:
为了得到index值作为list/list的tupleS代表Index/MultiIndex做到：
df.index.values.tolist() # an ndarray method, you probably shouldn't depend on this
or
或者
list(df.index.values) # this will always work in pandas
回答by smci
If you're only getting these to manually pass into df.set_index(), that's unnecessary. Just directly do df.set_index['your_col_name', drop=False], already.
如果您只是让这些手动传递到df.set_index()，那是不必要的。直接做df.set_index['your_col_name', drop=False]，已经。
It's very rare in pandas that you need to get an index as a Python list (unless you;re doing something pretty funky, or else passing them back to NumPy), so if you're doing this a lot, it's a code smell that you're doing something wrong.
在 Pandas 中，很少需要将索引作为 Python 列表获取（除非你正在做一些非常时髦的事情，或者将它们传递回 NumPy），所以如果你经常这样做，这是一种代码气味你做错了什么。
