eclipse 堆栈数组
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array of stacks
提问by harto
Is it possible to create an array of stacks without having to cast the stacks as they come out? Eclipse gives me a warning about not being able to make a generic array of Stack when I do something like this:
是否可以创建一个堆栈数组而不必在堆栈出现时进行转换？当我执行以下操作时，Eclipse 会警告我无法创建通用的 Stack 数组：
Stack<Card>[] cards = new Stack<Card>[52];
回答by harto
Joshua Bloch does an excellent job of describing this problem in Effective Java, Second Edition. Check out the relevant section on Google Book Search.
Joshua Bloch 在Effective Java, Second Edition 中出色地描述了这个问题。查看 Google 图书搜索的相关部分。
The advice he offers is to prefer lists to arrays. Your code might then look something like:
他提供的建议是更喜欢列表而不是数组。您的代码可能如下所示：
List<Stack<Card>> cards = new ArrayList<Stack<Card>>();
回答by Peter Lawrey
You can do the following, though this gives you a compiler "unchecked" warning.
您可以执行以下操作，尽管这会给您一个编译器“未经检查”的警告。
Stack<Card>[] cards = (Stack<Card>[]) new Stack[52];
回答by Peter Lawrey
Stack<Card>[] decks = new Stack[9]; // Declare
Card c = decks[5].pop(); // This compiles - java 'knows' the type
Integer i = decks[4].pop(); // This will not compile
回答by ?ukasz Bownik
Why do you use arrays anyway ?
你为什么要使用数组？
It is a low level programming structure.
它是一种低级编程结构。
Using Listor Setinstead (eg org.apache.commons.collections.list.LazyList) if you don't want to bother with innitialization.
如果您不想打扰初始化，请使用ListorSet代替（例如org.apache.commons.collections.list.LazyList）。
Or at least
或者至少
Arrays.asList(new Stack[52])to wrap an array into a list.
Arrays.asList(new Stack[52])将数组包装到列表中。
I couldnt reproduce jour error anywany .. :( perchaps it's because a different warning/errorlevel set.
我无论如何都无法重现 jour 错误.. :( 可能是因为设置了不同的警告/错误级别。
回答by Cogsy
It's to do with type erasure. Basically the generic types only exist at compile time and have no presence at run time
这与类型擦除有关。基本上泛型类型只在编译时存在，在运行时不存在
Have at look at this forum postfor a better explanation.
看看这个论坛帖子以获得更好的解释。
回答by Norbert Hartl
Well, the array does not need to be a generic because he is always defined as this. Why do you think you have to cast? I think that eclipse is somewhat confused here.
好吧，数组不需要是泛型的，因为他总是这样定义的。为什么你认为你必须投？我认为 eclipse 在这里有些混乱。
