Python Selenium 调试：元素在 (X,Y) 点不可点击

Selenium-Debugging: Element is not clickable at point (X,Y)

提问by parik

I try to scrape this siteby Selenium.

我尝试通过 Selenium抓取这个网站。

I want to click in "Next Page" buttom, for this I do:

我想点击“下一页”按钮，为此我这样做：

 driver.find_element_by_class_name('pagination-r').click()

it works for many pages but not for all, I got this error

它适用于许多页面但不适用于所有页面，我收到此错误

WebDriverException: Message: Element is not clickable at point (918, 13). Other element would receive the click: <div class="linkAuchan"></div>

always for this page

总是为这个页面

I read this question

我读了这个问题

and I tried this

我试过这个

driver.implicitly_wait(10)
el = driver.find_element_by_class_name('pagination-r')
action = webdriver.common.action_chains.ActionChains(driver)
action.move_to_element_with_offset(el, 918, 13)
action.click()
action.perform()

but I got the same error

但我遇到了同样的错误

回答by RemcoW

Another element is covering the element you are trying to click. You could use execute_script()to click on this.

另一个元素覆盖了您尝试单击的元素。你可以execute_script()用来点击这个。

element = driver.find_element_by_class_name('pagination-r')
driver.execute_script("arguments[0].click();", element)

回答by Deepak Garud

I had a similar issue where using ActionChains was not solving my error: WebDriverException: Message: unknown error: Element is not clickable at point (5 74, 892)

我有一个类似的问题，即使用 ActionChains 无法解决我的错误：WebDriverException: Message: unknown error: Element is not clickable at point (5 74, 892)

I found a nice solution if you dont want to use execute_script:

如果您不想使用execute_script，我找到了一个不错的解决方案：

    from selenium.webdriver.common.keys import Keys #need to send keystrokes

    inputElement = self.driver.find_element_by_name('checkout')

    inputElement.send_keys("\n") #send enter for links, buttons

or

或者

    inputElement.send_keys(Keys.SPACE) #for checkbox etc

回答by Rakesh Raut

Use explicit wait instead of implicit.

使用显式等待而不是隐式等待。

 new WebDriverWait(TestingSession.Browser.WebDriver, TimeSpan.FromSeconds(10)).Until(ExpectedConditions.ElementExists((By.ClassName("pagination-r'")))); 

回答by quickauto

If you are receiving an element not clickableerror, even after using wait on the element, try one of these workarounds:

如果您收到element not clickable错误消息，即使在对元素使用 wait 之后，请尝试以下解决方法之一：

• Use Actionto move to the location of elementand then run performon action

• 使用Action移动到的位置element，然后运行perform上action

WebElement element = driver.findElement(By("element_path"));
Actions actions = new Actions(driver);
actions.moveToElement(element).click().perform();`

• Check for an overlay or spinner on the elementand waitfor its invisibility

• 检查的覆盖或微调element，并wait为它的隐蔽性

By spinnerimg = By.id("spinner ID");
WebDriverWait wait = new WebDriverWait(driver, timeOutInSeconds);
wait.until(ExpectedConditions.invisibilityOfElementLocated(spinnerimg ));

Hope this helps

希望这可以帮助

回答by Chetan Kolhe

I have written logic to handle these type of exception .

我已经编写了处理这些类型异常的逻辑。

def find_element_click(self, by, expression, search_window=None, timeout=32, ignore_exception=[],
                       poll_frequency=4):
    """It find the element and click then  handle all type of exception during click

    :param poll_frequency:
    :param by:
    :param expression:
    :param timeout:
    :param ignore_exception:
    :return:
    """
    ignore_exception.append(NoSuchElementException)
    if search_window is None:
        search_window = self.driver

    end_time = time.time() + timeout
    while True:
        try:
            web_element = search_window.find_element(by=by, value=expression)
            web_element.click()
            return True
        except tuple(ignore_exception) as e:
            self.logger.debug(str(e))
            if time.time() > end_time:
                self.logger.exception(e)
                time.sleep(poll_frequency)
                break
        except Exception as e:
            raise
    self.logger.debug("Not able to click the element")
    return False