如何在 bash 中取消引用符号链接？
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How can I derefence symbolic links in bash?
提问by David Dean
How can I take any given path in bashand convert it to it's canonical form, dereferencing any symbolic links that may be contained within the path?
我怎样才能将任何给定的路径bash转换为它的规范形式，取消引用路径中可能包含的任何符号链接？
For example:
例如：
~$ mkdir /tmp/symtest
~$ cd /tmp/symtest/
/tmp/symtest$ mkdir -p foo/bar cat/dog
/tmp/symtest$ cd foo/bar/
/tmp/symtest/foo/bar$ ln -s ../../cat cat
/tmp/symtest/foo/bat$ cd ../../
/tmp/symtest$ tree
.
|-- cat
| `-- dog
`-- foo
`-- bar
`-- cat -> ../../cat
6 directories, 0 files
How can I get the full canonical path of /tmp/symtest/foo/bar/cat(i.e: /tmp/symtest/cat)?
我怎样才能获得/tmp/symtest/foo/bar/cat（即：）的完整规范路径/tmp/symtest/cat？
回答by David Dean
Thanks to Andy Skelton, it appears the answer is readlink -f:
感谢Andy Skelton，答案似乎是readlink -f：
$:/tmp/symtest$ readlink -f /tmp/symtest/foo/bar/cat
/tmp/symtest/cat
回答by usbdongle
Here's a function that will resolve symbolic links
It's original purpose is to resolve the full path to the calling script
pointed to by a /usr/bin symlink
这是一个将解析符号链接的函数
它的原始目的是解析 /usr/bin 符号链接指向的调用脚本的完整路径
# resolve symbolic links
function resolve_link() {
local LINK_FILE=${1:-${BASH_SOURCE[0]}}
local FILE_TYPE=`file $LINK_FILE | awk '{print }'`
local LINK_TO=$LINK_FILE
while [ $FILE_TYPE = "symbolic" ]; do
LINK_TO=`readlink $LINK_FILE`
FILE_TYPE=`file $LINK_TO | awk '{print }'`
done
echo $LINK_TO
}
BASH_SOURCE_RESOLVED=$(resolve_link)
echo $BASH_SOURCE_RESOLVED
It doesn't use recursion but then again I've never used recursion in bash
它不使用递归，但我从来没有在 bash 中使用过递归
