Python 3 获取和解析 JSON API
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Python 3 Get and parse JSON API
提问by ClickThisNick
How would I parse a json api response with python? I currently have this:
我将如何用 python 解析 json api 响应？我目前有这个：
import urllib.request
import json
url = 'https://hacker-news.firebaseio.com/v0/topstories.json?print=pretty'
def response(url):
with urllib.request.urlopen(url) as response:
return response.read()
res = response(url)
print(json.loads(res))
I'm getting this error: TypeError: the JSON object must be str, not 'bytes'
我收到此错误：TypeError: the JSON object must be str, not 'bytes'
What is the pythonic way to deal with json apis?
处理json apis的pythonic方式是什么？
采纳答案by ferdy
Version 1: (do a pip install requestsbefore running the script)
版本1：（pip install requests在运行脚本之前做一个）
import requests
r = requests.get(url='https://hacker-news.firebaseio.com/v0/topstories.json?print=pretty')
print(r.json())
Version 2: (do a pip install wgetbefore running the script)
版本 2 :(pip install wget在运行脚本之前做一个）
import wget
fs = wget.download(url='https://hacker-news.firebaseio.com/v0/topstories.json?print=pretty')
with open(fs, 'r') as f:
content = f.read()
print(content)
回答by gtlambert
I would usually use the requestspackage with the jsonpackage. The following code should be suitable for your needs:
我通常会使用requests带有json包的包。以下代码应该适合您的需求：
import requests
import json
url = 'https://hacker-news.firebaseio.com/v0/topstories.json?print=pretty'
r = requests.get(url)
print(json.loads(r.content))
Output
输出
[11008076,
11006915,
11008202,
....,
10997668,
10999859,
11001695]
回答by mimin0
you can use standard library python3:
您可以使用标准库python3：
import urllib.request
import json
url = 'http://www.reddit.com/r/all/top/.json'
req = urllib.request.Request(url)
##parsing response
r = urllib.request.urlopen(req).read()
cont = json.loads(r.decode('utf-8'))
counter = 0
##parcing json
for item in cont['data']['children']:
counter += 1
print("Title:", item['data']['title'], "\nComments:", item['data']['num_comments'])
print("----")
##print formated
#print (json.dumps(cont, indent=4, sort_keys=True))
print("Number of titles: ", counter)
output will be like this one:
输出将是这样的：
...
Title: Maybe we shouldn't let grandma decide things anymore.
Comments: 2018
----
Title: Carrie Fisher and Her Stunt Double Sunbathing on the Set of Return of The Jedi, 1982
Comments: 880
----
Title: fidget spinner
Comments: 1537
----
Number of titles: 25
回答by kartik
With Python 3
使用 Python 3
import requests
import json
url = 'http://IP-Address:8088/ws/v1/cluster/scheduler'
r = requests.get(url)
data = json.loads(r.content.decode())
回答by Jacques
The only thing missing in the original question is a call to the decodemethod on the response object (and even then, not for every python3 version). It's a shame no one pointed that out and everyone jumped on a third party library.
原始问题中唯一缺少的是decode对响应对象上的方法的调用（即使如此，也不是针对每个 python3 版本）。很遗憾没有人指出这一点，每个人都跳上了第三方库。
Using only the standard library, for the simplest of use cases :
对于最简单的用例，仅使用标准库：
import json
from urllib.request import urlopen
def get(url, object_hook=None):
with urlopen(url) as resource: # 'with' is important to close the resource after use
return json.load(resource, object_hook=object_hook)
Simple use case :
简单用例：
data = get('http://url') # '{ "id": 1, "$key": 13213654 }'
print(data['id']) # 1
print(data['$key']) # 13213654
Or if you prefer, but riskier :
或者，如果您愿意，但风险更大：
from types import SimpleNamespace
data = get('http://url', lambda o: SimpleNamespace(**o)) # '{ "id": 1, "$key": 13213654 }'
print(data.id) # 1
print(data.$key) # invalid syntax
# though you can still do
print(data.__dict__['$key'])
