Java JSON 发布到 Spring Controller
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JSON post to Spring Controller
提问by user2239655
Hi I am starting with Web Services in Spring, so I am trying to develop small application in Spring + JSON + Hibernate. I have some problem with HTTP-POST. I created a method:
嗨，我从 Spring 中的 Web 服务开始，所以我正在尝试在 Spring + JSON + Hibernate 中开发小型应用程序。我对 HTTP-POST 有一些问题。我创建了一个方法：
@RequestMapping(value="/workers/addNewWorker", method = RequestMethod.POST, produces = "application/json", consumes = "application/json")
@ResponseBody
public String addNewWorker(@RequestBody Test test) throws Exception {
String name = test.name;
return name;
}
And my model Test looks like:
我的模型 Test 看起来像：
public class Test implements Serializable {
private static final long serialVersionUID = -1764970284520387975L;
public String name;
public Test() {
}
}
By POSTMAN I am sending simply JSON {"name":"testName"} and I always get error;
通过邮递员，我只发送 JSON {"name":"testName"} 并且我总是收到错误；
The server refused this request because the request entity is in a format not supported by the requested resource for the requested method.
I imported Hymanson library. My GET methods works fine. I don't know what I'm doing wrong. I am grateful for any suggestions.
我导入了Hyman逊图书馆。我的 GET 方法工作正常。我不知道我做错了什么。我很感激任何建议。
采纳答案by Vineeth Bhaskaran
Convert your JSON object to JSON String using
使用将您的 JSON 对象转换为 JSON 字符串
JSON.stringify({"name":"testName"})
JSON.stringify({"name":"testName"})
or manually. @RequestBody expecting json stringinstead of json object.
或手动。@RequestBody 需要 json 字符串而不是 json 对象。
Note:stringify function having issue with some IE version, firefox it will work
注意：stringify 函数在某些 IE 版本中存在问题，firefox 可以使用
verify the syntax of your ajax request for POST request. processData:falseproperty is required in ajax request
验证 POST 请求的 ajax 请求的语法。processData:false属性在 ajax 请求中是必需的
$.ajax({
url:urlName,
type:"POST",
contentType: "application/json; charset=utf-8",
data: jsonString, //Stringified Json Object
async: false, //Cross-domain requests and dataType: "jsonp" requests do not support synchronous operation
cache: false, //This will force requested pages not to be cached by the browser
processData:false, //To avoid making query String instead of JSON
success: function(resposeJsonObject){
// Success Action
}
});
Controller
控制器
@RequestMapping(value = urlPattern , method = RequestMethod.POST)
public @ResponseBody Test addNewWorker(@RequestBody Test jsonString) {
//do business logic
return test;
}
@RequestBody-Covert Json object to java
@RequestBody- 将 Json 对象转换为 Java
@ResponseBody- convert Java object to json
@ResponseBody- 将 Java 对象转换为 json
回答by Vin Tsie
Try to using application/* instead. And use JSON.maybeJson() to check the data structure in the controller.
尝试使用 application/* 代替。并使用 JSON.maybeJson() 检查控制器中的数据结构。
回答by Aman Goel
Do the following thing if you want to use json as a http request and response. So we need to make changes in [context].xml
如果您想使用 json 作为 http 请求和响应，请执行以下操作。所以我们需要在 [context].xml 中进行更改
<!-- Configure to plugin JSON as request and response in method handler -->
<beans:bean class="org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerAdapter">
<beans:property name="messageConverters">
<beans:list>
<beans:ref bean="jsonMessageConverter"/>
</beans:list>
</beans:property>
</beans:bean>
<!-- Configure bean to convert JSON to POJO and vice versa -->
<beans:bean id="jsonMessageConverter" class="org.springframework.http.converter.json.MappingHymanson2HttpMessageConverter">
</beans:bean>
MappingHymanson2HttpMessageConverter to the RequestMappingHandlerAdapter messageConverters so that Hymanson API kicks in and converts JSON to Java Beans and vice versa. By having this configuration, we will be using JSON in request body and we will receive JSON data in the response.
MappingHymanson2HttpMessageConverter 到 RequestMappingHandlerAdapter messageConverters 以便 Hymanson API 启动并将 JSON 转换为 Java Beans，反之亦然。通过此配置，我们将在请求正文中使用 JSON，我们将在响应中接收 JSON 数据。
I am also providing small code snippet for controller part:
我还为控制器部分提供了小代码片段：
@RequestMapping(value = EmpRestURIConstants.DUMMY_EMP, method = RequestMethod.GET)
public @ResponseBody Employee getDummyEmployee() {
logger.info("Start getDummyEmployee");
Employee emp = new Employee();
emp.setId(9999);
emp.setName("Dummy");
emp.setCreatedDate(new Date());
empData.put(9999, emp);
return emp;
}
So in above code emp object will directly convert into json as a response. same will happen for post also.
所以在上面的代码中，emp 对象将直接转换为 json 作为响应。帖子也会发生同样的情况。
回答by Ameya Pandilwar
You need to include the getters and setters for all the fields that have been defined in the model Testclass --
您需要为模型Test类中定义的所有字段包含 getter 和 setter——
public class Test implements Serializable {
private static final long serialVersionUID = -1764970284520387975L;
public String name;
public Test() {
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
