PHP 日期格式、删除时间等
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时间：2020-08-25 03:36:00 来源:igfitidea点击:
PHP date format, remove time and more
提问by itsme
Possible Duplicate:
Convert one date format into another in PHP
可能的重复：
在 PHP 中将一种日期格式转换为另一种格式
Starting from:
从...开始：
$date = '2012-09-09 03:09:00'
I would like to do two things.
我想做两件事。
- Remove the time from the string, so it will become
"2012-09-09". - Calculate how many years, days, and hours have passed since this date using the server current date/time/timezone.
- 从字符串中删除时间，因此它将变为
"2012-09-09". - 使用服务器当前日期/时间/时区计算自该日期以来已经过去了多少年、多少天和多少小时。
Could anyone help me figure this out?
谁能帮我解决这个问题？
回答by Mihai Iorga
Use DateTime:
使用日期时间：
$date = '2012-09-09 03:09:00';
$createDate = new DateTime($date);
$strip = $createDate->format('Y-m-d');
var_dump($strip); // string(10) "2012-09-09"
$now = new DateTime();
$difference = $now->diff($createDate, true);
var_dump($difference);
/* object(DateInterval)#3 (8) {
["y"]=>
int(0)
["m"]=>
int(0)
["d"]=>
int(7)
["h"]=>
int(13)
["i"]=>
int(4)
["s"]=>
int(38)
["invert"]=>
int(0)
["days"]=>
int(7)
} */
回答by JvdBerg
$date = '2012-09-09 03:09:00';
$dt = new DateTime($date);
echo $dt->format('Y-m-d');
$interval = $dt->diff(new DateTime());
You can use the interval as it suits you. See http://php.net/manual/en/class.dateinterval.php
您可以使用适合您的间隔。见http://php.net/manual/en/class.dateinterval.php
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