使用 jquery 只允许 2 个小数点输入到文本框?

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时间:2020-08-26 18:24:52  来源:igfitidea点击:

Allow only 2 decimal points entry to a textbox using jquery?

javascriptjqueryregex

提问by R J.

Allow only 2 decimal points when entering number to a textbox using jquery.

使用 jquery 在文本框中输入数字时只允许 2 个小数点。

Please suggest any regex to allow only two decimal in textbox.

请建议任何正则表达式在文本框中只允许两位小数。

I have tried the following code.

我试过下面的代码。

$("#amountId").val().replace (/(\.\d\d)\d+|([\d.]*)[^\d.]/, '');

回答by A. Wolff

You could do it without regex:

你可以在没有正则表达式的情况下做到这一点:

var dec = parseFloat($("#amountId").val(),10).toFixed(2);

回答by Vishal Surjuse

HTML:

HTML:

<input type="text" class="maskedExt" maskedFormat="3,2" />
 maskedFormat="number count before decimal point, number count after decimal point"

Script:

脚本:

$(document).ready(function () {
    $('body').on('keyup', '.maskedExt', function () {
        var num = $(this).attr("maskedFormat").toString().split(',');
        var regex = new RegExp("^\d{0," + num[0] + "}(\.\d{0," + num[1] + "})?$");
        if (!regex.test(this.value)) {
            this.value = this.value.substring(0, this.value.length - 1);
        }
    });
});

回答by Mr_Green

I was just testing using regex to learn it. But I recommend going with roasted's solution.

我只是在测试使用正则表达式来学习它。但我建议使用烤的解决方案。

<input id="txtId" type="text"></input>


var txt = document.getElementById('txtId');
txt.addEventListener('keyup', myFunc);

function myFunc(e) {
    var val = this.value;
    var re = /^([0-9]+[\.]?[0-9]?[0-9]?|[0-9]+)$/g;
    var re1 = /^([0-9]+[\.]?[0-9]?[0-9]?|[0-9]+)/g;
    if (re.test(val)) {
        //do something here

    } else {
        val = re1.exec(val);
        if (val) {
            this.value = val[0];
        } else {
            this.value = "";
        }
    }
}

Working Fiddle

工作小提琴

回答by Devraj Gadhavi

Another working solution

另一个工作解决方案

Html

html

<input type="text" id="myTextBox" class="two-decimals">

jQuery

jQuery

$(".two-decimals").on("keypress", function (evt) {
        var $txtBox = $(this);
        var charCode = (evt.which) ? evt.which : evt.keyCode
        if (charCode > 31 && (charCode < 48 || charCode > 57) && charCode != 46)
            return false;
        else {
            var len = $txtBox.val().length;
            var index = $txtBox.val().indexOf('.');
            if (index > 0 && charCode == 46) {
              return false;
            }
            if (index > 0) {
                var charAfterdot = (len + 1) - index;
                if (charAfterdot > 3) {
                    return false;
                }
            }
        }
        return $txtBox; //for chaining
    });

回答by Snehal Chavan

function checkDecimal(el){
 var ex = /^[0-9]+\.?[0-9]*$/;
  if(ex.test(el.value)==false){
   el.value = el.value.substring(0,el.value.length - 1);
  }
}