bash 使用变量作为行号从bash脚本中的文件中读取特定行
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reading a particular line from a file in bash script using variable as line number
提问by user3286661
I have a csv file which contains a large number of entries. I have to read certain lines from the file. The line number is stored in a variable called lineno.
How to accomplish this?It may look something like:
我有一个包含大量条目的 csv 文件。我必须从文件中读取某些行。行号存储在名为lineno的变量中。
如何做到这一点？它可能看起来像：
line=$(sed -n "($lineno)p")
I want to know the correct syntax to do this.
Thanks
我想知道正确的语法来做到这一点。
谢谢
回答by kojiro
You pretty much have it.
你几乎拥有它。
line=$(sed -n "${lineno}p" "$file")
