VBA 和私有函数
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VBA and Private Functions
提问by Nick Heiner
For some reason, nothing happens when I run this macro. What might I be doing wrong?
出于某种原因，当我运行这个宏时没有任何反应。我可能做错了什么？
(I'm trying to fill each cell in the range with a randomly selected string.)
（我试图用随机选择的字符串填充范围内的每个单元格。）
Sub ktr()
Dim dataRange As Range
Set dataRange = Range("A1:V35")
For Each cell In dataRange
response = azerothSays()
cell.Value = response
Next cell
End Sub
Private Function azerothSays()
Dim result As String
Select Case Rnd(6)
Case 1
result = "CELIBACY"
Case 2
result = "WORMS"
Case 3
result = "AGING"
Case 4
result = "MARRIAGE"
Case 5
result = "CHEMISTRY"
Case 6
result = "DISINTIGRATE"
End Select
azerothSays = result
End Function
回答by JohnK813
Rnd() always produces a (decimal) number between 0 and 1. So, if you wanted to get a random number from 1 to 6, try replacing your Select Case line with this:
Rnd() 总是产生一个介于 0 和 1 之间的（十进制）数。所以，如果你想得到一个从 1 到 6 的随机数，试着用这个替换你的 Select Case 行：
Select Case Int((6 * Rnd) + 1)
The "math part" finds a number between 1 and 6, and Int() converts it to a whole number.
“数学部分”查找 1 到 6 之间的数字，Int() 将其转换为整数。
In general, the formula is
一般来说，公式是
Int ((upperbound - lowerbound + 1) * Rnd + lowerbound)
回答by user151019
John beat me to the comment re RND but that is not the only problem.
约翰击败了我对 RND 的评论，但这不是唯一的问题。
First is a stylistic issue. If you have a select case statement the always include a case else. In you code this is what would have been executed. If you stepped through the code with a debugger you would have seen the issue for yourself.
首先是文体问题。如果您有一个 select case 语句，则始终包含一个 case else。在您的代码中，这就是执行的内容。如果您使用调试器单步调试代码，您就会亲眼看到这个问题。
Also for each cell in range does not seem to act as you wish. In Excel 2004 you get an empty value back
此外，范围内的每个单元格似乎都没有按您的意愿行事。在 Excel 2004 中，您会得到一个空值
I would really look at the examples in the Excel help. It has one for cells property example shhowing how to set the values in a range.
我真的会看看 Excel 帮助中的示例。它有一个单元格属性示例，展示了如何在一个范围内设置值。
In this case more like (depending on what option base is set to)
在这种情况下更像是（取决于设置的选项基数）
for row = 1 to 21
for col = 1 to 35
dataRange.Cells(Row, col).Value = azerothSays()
next
next
To make debugging easier I would have coded the rando bit in the function as
为了使调试更容易，我会将函数中的rando位编码为
Dim r as integer
r = Int((6 * Rnd) + 1)
Select Case (r)
Then you can see what the random number is in the debugger
然后就可以在调试器中看到随机数是什么了
