javascript 针对javascript中的多个正则表达式的测试字符串
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/10921321/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
test string against multiple regexes in javascript
提问by mark
I want to test a given string against 20 or so regular expressions. What's a clean way to do this in Javascript? I'm more concerned about clean code and readability than efficiency (but I don't want it to be super slow either).
我想针对 20 个左右的正则表达式测试给定的字符串。在 Javascript 中执行此操作的干净方法是什么？我更关心干净的代码和可读性而不是效率（但我也不希望它超级慢）。
Right now I have:
现在我有：
if (href.indexOf('apple.com') > -1 ||
href.indexOf('google.com') > -1 ||
href.indexOf('yahoo.com') > -1 ||
href.indexOf('facebook.com') > -1) {
performDarkMagic()
}
But it's going to start looking kind of messy as that list grows. Maybe I could just create an array of regular expressions and execute something like _.any() and apply regex.test on each?
但随着该列表的增长，它会开始看起来有点混乱。也许我可以创建一个正则表达式数组并执行诸如 _.any() 之类的东西并在每个表达式上应用 regex.test ？
Edit: the strings/regexes to match may become more complicated, I just used simple URLs to make the example readable.
编辑：要匹配的字符串/正则表达式可能会变得更复杂，我只是使用简单的 URL 使示例可读。
回答by Larry Battle
Use the test function for regular expressions.
对正则表达式使用 test 函数。
More information on regular expressions here. https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/RegExp
有关正则表达式的更多信息，请点击此处。 https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/RegExp
var re = /((google)|(facebook)|(yahoo)|(apple))\.com/;
re.test( str ); // returns true or false;
Test cases.
测试用例。
Live Demo Here: http://jsfiddle.net/rkzXP/1/
现场演示：http: //jsfiddle.net/rkzXP/1/
var func = function( str ){
var re = /((google)|(facebook)|(yahoo)|(apple))\.com/;
return re.test( str );
};
test("test for valid values", function() {
equal( func("google.com"), true);
equal( func("facebook.com"), true);
equal( func("apple.com"), true);
});
test("test for invalid values", function() {
equal( func("googl.com"), false);
equal( func("faceook.com"), false);
equal( func("apple"), false);
});
So you can rewrite your code as the following.
因此，您可以将代码重写为如下所示。
var re = /((google)|(facebook)|(yahoo)|(apple))\.com/;
if( re.test(str) ){
performDarkMagic()
}
回答by Hunter McMillen
var patterns = ['apple.com', 'google.com', 'yahoo.com', 'facebook.com', ...]
var callFunc = false;
patterns.forEach(function(item){
if(href.indexOf(item) > -1){
callFunc = true;
break;
}
});
if(callFunc) {
performDarkMagic();
}
回答by Bergi
Yes, building an array and using .any()or .some()is just fine, especially when there will be more than 4 values:
是的，构建一个数组并使用.any()or.some()就好了，尤其是当有超过 4 个值时：
if (["apple","google","yahoo","facebook"].some(host => href.includes(`${host}.com`)) {
performLightMagic();
}
Yet I can't see regexes there, there are just strings; so you could simplify using regex.test()to:
但是我在那里看不到正则表达式，只有字符串；所以你可以简化使用regex.test()：
if (/apple\.com|google\.com|yahoo\.com|facebook\.com/.test(href)) { performLightMagic(); }
or even
甚至
if (/(apple|google|yahoo|facebook)\.com/.test(href)) { performLightMagic(); }
回答by Daniel A. White
You could put each one in array then looping over each.
你可以把每个都放在数组中，然后循环遍历每个。
回答by tronbabylove
How I would do it: factor it out into a function. Put each regex in an array, loop over them and return true the first time indexOf > -1. If you reach the end of the loop return false.
我会怎么做：把它分解成一个函数。将每个正则表达式放入一个数组中，循环它们并在第一次 indexOf > -1 时返回 true。如果到达循环末尾，则返回 false。
回答by Nicolás Torres
Loop through a regex array and then do:
循环遍历一个正则表达式数组，然后执行：
result=result AND (result_of_regex);
next;
after the loop return result
循环返回结果后
