jQuery 查找并替换为数组
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jQuery find and replace with arrays
提问by champton
I need to search an input's value for all street abbreviations and replace with appropriate suffix. This is what I have so far:
我需要搜索所有街道缩写的输入值并替换为适当的后缀。这是我到目前为止：
jQuery('#colCenterAddress').val(function(i,val) {
var f = ['Rd','St','Ave'];
var r = ['Road','Street','Avenue'];
return val.replace(f,r);
});
Thoughts?
想法？
回答by
You need to iterate the fArray, and try each replace separately.
您需要迭代f数组，并分别尝试每个替换。
jQuery('#colCenterAddress').val(function(i,val) {
var f = ['Rd','St','Ave'];
var r = ['Road','Street','Avenue'];
$.each(f,function(i,v) {
val = val.replace(new RegExp('\b' + v + '\b', 'g'),r[i]);
});
return val;
});
DEMO:http://jsfiddle.net/vRTNt/
演示：http : //jsfiddle.net/vRTNt/
If this is something you're going to do on a regular basis, you may want to store the Arrays, and even make a third Array that has the pre-made regular expressions.
如果这是您要定期执行的操作，您可能希望存储数组，甚至创建具有预制正则表达式的第三个数组。
var f = ['Rd','St','Ave'];
var r = ['Road','Street','Avenue'];
var re = $.map(f, function(v,i) {
return new RegExp('\b' + v + '\b', 'g');
});
jQuery('#colCenterAddress').val(function(i,val) {
$.each(f,function(i,v) {
val = val.replace(re[i],r[i]);
});
return val;
});
回答by RonnyKnoxville
var valArray = val.split(" ");
for(x = 0; x < valArray.length; x++){
for(y = 0; y < r.length; y ++){
if (valArray[x] == f[y]){
valArray[x] = r[y];
}
}
}
return valArray
You could always turn the array back into a string for the return if you like.
如果您愿意，您始终可以将数组转换回字符串以供返回。
回答by Rocket Hazmat
One way to do this, is to loop through the valstring, and if you see a word in the farray, replace it with its counterpart in the rarray.
一种方法是循环遍历val字符串，如果您在f数组中看到一个单词，请将其替换为r数组中的对应词。
jQuery('#colCenterAddress').val(function(i,val) {
var f = ['Rd','St','Ave'];
var r = ['Road','Street','Avenue'];
var valArray = val.split(' ');
$.each(valArray, function(i,v){
var inF = $.inArray(v, f);
if(inF !== -1){
valArray[i] = v.replace(f[inF], r[inF]);
}
});
return valArray.join(' ');
});
