vba 在 access 97 中找到完整路径的目录部分（减去文件名）
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Find the directory part (minus the filename) of a full path in access 97
提问by apenwarr
For various reasons, I'm stuck in Access 97 and need to get only the path part of a full pathname.
由于各种原因，我被困在 Access 97 中，只需要获取完整路径名的路径部分。
For example, the name
例如，名称
c:\whatever dir\another dir\stuff.mdb
should become
应该成为
c:\whatever dir\another dir\
This site has some suggestions on how to do it: http://www.ammara.com/access_image_faq/parse_path_filename.html
这个网站有一些关于如何做的建议：http: //www.ammara.com/access_image_faq/parse_path_filename.html
But they seem rather hideous. There must be a better way, right?
但他们看起来相当可怕。一定有更好的方法吧？
采纳答案by DJ.
That's about it. There is no magic built-in function...
就是这样。没有神奇的内置功能......
回答by Makah
You can do something simple like: Left(path, InStrRev(path, "\"))
你可以做一些简单的事情，比如： Left(path, InStrRev(path, "\"))
Example:
例子：
Function GetDirectory(path)
GetDirectory = Left(path, InStrRev(path, "\"))
End Function
回答by John Mo
I always used the FileSystemObjectfor this sort of thing. Here's a little wrapper function I used. Be sure to reference the Microsoft Scripting Runtime.
我总是将FileSystemObject用于这种事情。这是我使用的一个小包装函数。请务必参考Microsoft Scripting Runtime.
Function StripFilename(sPathFile As String) As String
'given a full path and file, strip the filename off the end and return the path
Dim filesystem As New FileSystemObject
StripFilename = filesystem.GetParentFolderName(sPathFile) & "\"
Exit Function
End Function
回答by Jeff Stander
This seems to work. The above doesn't in Excel 2010.
这似乎有效。以上不在 Excel 2010 中。
Function StripFilename(sPathFile As String) As String
'given a full path and file, strip the filename off the end and return the path
Dim filesystem As Object
Set filesystem = CreateObject("Scripting.FilesystemObject")
StripFilename = filesystem.GetParentFolderName(sPathFile) & "\"
Exit Function
End Function
回答by David-W-Fenton
If you're just needing the path of the MDB currently open in the Access UI, I'd suggest writing a function that parses CurrentDB.Name and then stores the result in a Static variable inside the function. Something like this:
如果您只需要当前在 Access UI 中打开的 MDB 的路径，我建议编写一个解析 CurrentDB.Name 的函数，然后将结果存储在函数内的静态变量中。像这样的东西：
Public Function CurrentPath() As String
Dim strCurrentDBName As String
Static strPath As String
Dim i As Integer
If Len(strPath) = 0 Then
strCurrentDBName = CurrentDb.Name
For i = Len(strCurrentDBName) To 1 Step -1
If Mid(strCurrentDBName, i, 1) = "\" Then
strPath = Left(strCurrentDBName, i)
Exit For
End If
Next
End If
CurrentPath = strPath
End Function
This has the advantage that it only loops through the name one time.
这样做的好处是它只循环名称一次。
Of course, it only works with the file that's open in the user interface.
当然，它只适用于在用户界面中打开的文件。
Another way to write this would be to use the functions provided at the linkinside the function above, thus:
另一种写法是使用上面函数内部链接中提供的函数，因此：
Public Function CurrentPath() As String
Static strPath As String
If Len(strPath) = 0 Then
strPath = FolderFromPath(CurrentDB.Name)
End If
CurrentPath = strPath
End Function
This makes retrieving the current path very efficient while utilizing code that can be used for finding the path for any filename/path.
这使得检索当前路径非常有效，同时利用可用于查找任何文件名/路径的路径的代码。
回答by Dick Kusleika
left(currentdb.Name,instr(1,currentdb.Name,dir(currentdb.Name))-1)
left(currentdb.Name,instr(1,currentdb.Name,dir(currentdb.Name))-1)
The Dir function will return only the file portion of the full path. Currentdb.Name is used here, but it could be any full path string.
Dir 函数将只返回完整路径的文件部分。此处使用 Currentdb.Name，但它可以是任何完整路径字符串。
回答by Sam
Try this function:
试试这个功能：
Function FolderPath(FilePath As String) As String
'--------------------------------------------------
'Returns the folder path form the file path.
'Written by: Christos Samaras
'Date: 06/11/2013
'--------------------------------------------------
Dim FileName As String
With WorksheetFunction
FileName = Mid(FilePath, .Find("*", .Substitute(FilePath, "\", "*", Len(FilePath) - _
Len(.Substitute(FilePath, "\", "")))) + 1, Len(FilePath))
End With
FolderPath = Left(FilePath, Len(FilePath) - Len(FileName) - 1)
End Function
If you don't want to remove the last backslash "\" at the end of the folder's path, change the last line with this:
如果您不想删除文件夹路径末尾的最后一个反斜杠“\”，请将最后一行更改为：
FolderPath = Left(FilePath, Len(FilePath) - Len(FileName))
Example:
例子：
FolderPath("C:\Users\Christos\Desktop\LAT Analysers Signal Correction\TP 14_03_2013_5.csv")
gives:
给出：
C:\Users\Christos\Desktop\LAT Analysers Signal Correction\1
C:\Users\Christos\Desktop\LAT Analyzers Signal Correction\1
or
或者
C:\Users\Christos\Desktop\LAT Analysers Signal Correction\1\
C:\Users\Christos\Desktop\LAT Analyzers Signal Correction\1\
in the second case (note that there is a backslash at the end).
在第二种情况下（注意末尾有一个反斜杠）。
I hope it helps...
我希望它有帮助...
回答by AlexFreyre
vFilename="C:\Informes\Indicadores\Program\Ind_Cont_PRv.txt"
vFilename="C:\Informes\Indicadores\Program\Ind_Cont_PRv.txt"
vDirFile = Replace(vFilename, Dir(vFileName, vbDirectory), "")
vDirFile = Replace(vFilename, Dir(vFileName, vbDirectory), "")
' Result=C:\Informes\Indicadores_Contraloria\Programa\Versiones anteriores\
' 结果=C:\Informes\Indicadores_Contraloria\Programa\Versiones前部\
回答by cadvena
If you are confident in your input parameters, you can use this single line of code which uses the native Split and Join functions and Excel native Application.pathSeparator.
如果您对输入参数有信心，则可以使用这一行代码，它使用本机 Split 和 Join 函数以及 Excel 本机 Application.pathSeparator。
Split(Join(Split(strPath, "."), Application.pathSeparator), Application.pathSeparator)
If you want a more extensivefunction, the code below is tested in Windows and should also work on Mac (though not tested). Be sure to also copy the supporting function GetPathSeparator, or modify the code to use Application.pathSeparator. Note, this is a first draft; I should really refactor it to be more concise.
如果你想要一个更广泛的功能，下面的代码在 Windows 中测试过，也应该在 Mac 上运行（虽然没有测试）。请务必同时复制支持函数 GetPathSeparator，或修改代码以使用 Application.pathSeparator。请注意，这是初稿；我真的应该重构它以使其更简洁。
Private Sub ParsePath2Test()
'ParsePath2(DrivePathFileExt, -2) returns a multi-line string for debugging.
Dim p As String, n As Integer
Debug.Print String(2, vbCrLf)
If True Then
Debug.Print String(2, vbCrLf)
Debug.Print ParsePath2("", -2)
Debug.Print ParsePath2("C:", -2)
Debug.Print ParsePath2("C:\", -2)
Debug.Print ParsePath2("C:\Windows", -2)
Debug.Print ParsePath2("C:\Windows\notepad.exe", -2)
Debug.Print ParsePath2("C:\Windows\SysWOW64", -2)
Debug.Print ParsePath2("C:\Windows\SysWOW64\", -2)
Debug.Print ParsePath2("C:\Windows\SysWOW64\AcLayers.dll", -2)
Debug.Print ParsePath2("C:\Windows\SysWOW64\.fakedir", -2)
Debug.Print ParsePath2("C:\Windows\SysWOW64\fakefile.ext", -2)
End If
If True Then
Debug.Print String(1, vbCrLf)
Debug.Print ParsePath2("\Windows", -2)
Debug.Print ParsePath2("\Windows\notepad.exe", -2)
Debug.Print ParsePath2("\Windows\SysWOW64", -2)
Debug.Print ParsePath2("\Windows\SysWOW64\", -2)
Debug.Print ParsePath2("\Windows\SysWOW64\AcLayers.dll", -2)
Debug.Print ParsePath2("\Windows\SysWOW64\.fakedir", -2)
Debug.Print ParsePath2("\Windows\SysWOW64\fakefile.ext", -2)
End If
If True Then
Debug.Print String(1, vbCrLf)
Debug.Print ParsePath2("Windows\notepad.exe", -2)
Debug.Print ParsePath2("Windows\SysWOW64", -2)
Debug.Print ParsePath2("Windows\SysWOW64\", -2)
Debug.Print ParsePath2("Windows\SysWOW64\AcLayers.dll", -2)
Debug.Print ParsePath2("Windows\SysWOW64\.fakedir", -2)
Debug.Print ParsePath2("Windows\SysWOW64\fakefile.ext", -2)
Debug.Print ParsePath2(".fakedir", -2)
Debug.Print ParsePath2("fakefile.txt", -2)
Debug.Print ParsePath2("fakefile.onenote", -2)
Debug.Print ParsePath2("C:\Personal\Workspace\Code\PythonVenvs\xlwings_test\.idea", -2)
Debug.Print ParsePath2("Windows", -2) ' Expected to raise error 52
End If
If True Then
Debug.Print String(2, vbCrLf)
Debug.Print "ParsePath2 ""\Windows\SysWOW64\fakefile.ext"" with different ReturnType values"
Debug.Print , "{empty}", "D", ParsePath2("Windows\SysWOW64\fakefile.ext")(1)
Debug.Print , "0", "D", ParsePath2("Windows\SysWOW64\fakefile.ext", 0)(1)
Debug.Print , "1", "ext", ParsePath2("Windows\SysWOW64\fakefile.ext", 1)
Debug.Print , "10", "file", ParsePath2("Windows\SysWOW64\fakefile.ext", 10)
Debug.Print , "11", "file.ext", ParsePath2("Windows\SysWOW64\fakefile.ext", 11)
Debug.Print , "100", "path", ParsePath2("Windows\SysWOW64\fakefile.ext", 100)
Debug.Print , "110", "path\file", ParsePath2("Windows\SysWOW64\fakefile.ext", 110)
Debug.Print , "111", "path\file.ext", ParsePath2("Windows\SysWOW64\fakefile.ext", 111)
Debug.Print , "1000", "D", ParsePath2("Windows\SysWOW64\fakefile.ext", 1000)
Debug.Print , "1100", "D:\path", ParsePath2("Windows\SysWOW64\fakefile.ext", 1100)
Debug.Print , "1110", "D:\p\file", ParsePath2("Windows\SysWOW64\fakefile.ext", 1110)
Debug.Print , "1111", "D:\p\f.ext", ParsePath2("Windows\SysWOW64\fakefile.ext", 1111)
On Error GoTo EH:
' This is expected to presetn an error:
p = "Windows\SysWOW64\fakefile.ext"
n = 1010
Debug.Print "1010", "D:\p\file.ext", ParsePath2("Windows\SysWOW64\fakefile.ext", 1010)
On Error GoTo 0
End If
Exit Sub
EH:
Debug.Print , CStr(n), "Error: "; Err.Number, Err.Description
Resume Next
End Sub
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Public Function ParsePath2(ByVal DrivePathFileExt As String _
, Optional ReturnType As Integer = 0)
' Writen by Chris Advena. You may modify and use this code provided you leave
' this credit in the code.
' Parses the input DrivePathFileExt string into individual components (drive
' letter, folders, filename and extension) and returns the portions you wish
' based on ReturnType.
' Returns either an array of strings (ReturnType = 0) or an individual string
' (all other defined ReturnType values).
'
' Parameters:
' DrivePathFileExt: The full drive letter, path, filename and extension
' ReturnType: -2 or a string up of to 4 ones with leading or lagging zeros
' (e.g., 0001)
' -2: special code for debugging use in ParsePath2Test().
' Results in printing verbose information to the Immediate window.
' 0: default: Array(driveStr, pathStr, fileStr, extStr)
' 1: extension
' 10: filename stripped of extension
' 11: filename.extension, excluding drive and folders
' 100: folders, excluding drive letter filename and extension
' 111: folders\filename.extension, excluding drive letter
' 1000: drive leter only
' 1100: drive:\folders, excluding filename and extension
' 1110: drive:\folders\filename, excluding extension
' 1010, 0101, 1001: invalid ReturnTypes. Will result raise error 380, Value
' is not valid.
Dim driveStr As String, pathStr As String
Dim fileStr As String, extStr As String
Dim drivePathStr As String
Dim pathFileExtStr As String, fileExtStr As String
Dim s As String, cnt As Integer
Dim i As Integer, slashStr As String
Dim dotLoc As Integer, slashLoc As Integer, colonLoc As Integer
Dim extLen As Integer, fileLen As Integer, pathLen As Integer
Dim errStr As String
DrivePathFileExt = Trim(DrivePathFileExt)
If DrivePathFileExt = "" Then
fileStr = ""
extStr = ""
fileExtStr = ""
pathStr = ""
pathFileExtStr = ""
drivePathStr = ""
GoTo ReturnResults
End If
' Determine if Dos(/) or UNIX(\) slash is used
slashStr = GetPathSeparator(DrivePathFileExt)
' Find location of colon, rightmost slash and dot.
' COLON: colonLoc and driveStr
colonLoc = 0
driveStr = ""
If Mid(DrivePathFileExt, 2, 1) = ":" Then
colonLoc = 2
driveStr = Left(DrivePathFileExt, 1)
End If
#If Mac Then
pathFileExtStr = DrivePathFileExt
#Else ' Windows
pathFileExtStr = ""
If Len(DrivePathFileExt) > colonLoc _
Then pathFileExtStr = Mid(DrivePathFileExt, colonLoc + 1)
#End If
' SLASH: slashLoc, fileExtStr and fileStr
' Find the rightmost path separator (Win backslash or Mac Fwdslash).
slashLoc = InStrRev(DrivePathFileExt, slashStr, -1, vbBinaryCompare)
' DOT: dotLoc and extStr
' Find rightmost dot. If that dot is not part of a relative reference,
' then set dotLoc. dotLoc is meant to apply to the dot before an extension,
' NOT relative path reference dots. REl ref dots appear as "." or ".." at
' the very leftmost of the path string.
dotLoc = InStrRev(DrivePathFileExt, ".", -1, vbTextCompare)
If Left(DrivePathFileExt, 1) = "." And dotLoc <= 2 Then dotLoc = 0
If slashLoc + 1 = dotLoc Then
dotLoc = 0
If Len(extStr) = 0 And Right(pathFileExtStr, 1) <> slashStr _
Then pathFileExtStr = pathFileExtStr & slashStr
End If
#If Not Mac Then
' In windows, filenames cannot end with a dot (".").
If dotLoc = Len(DrivePathFileExt) Then
s = "Error in FileManagementMod.ParsePath2 function. " _
& "DrivePathFileExt " & DrivePathFileExt _
& " cannot end iwth a dot ('.')."
Err.Raise 52, "FileManagementMod.ParsePath2", s
End If
#End If
' extStr
extStr = ""
If dotLoc > 0 And (dotLoc < Len(DrivePathFileExt)) _
Then extStr = Mid(DrivePathFileExt, dotLoc + 1)
' fileExtStr
fileExtStr = ""
If slashLoc > 0 _
And slashLoc < Len(DrivePathFileExt) _
And dotLoc > slashLoc Then
fileExtStr = Mid(DrivePathFileExt, slashLoc + 1)
End If
' Validate the input: DrivePathFileExt
s = ""
#If Mac Then
If InStr(1, DrivePathFileExt, ":") > 0 Then
s = "DrivePathFileExt ('" & DrivePathFileExt _
& "')has invalid format. " _
& "UNIX/Mac filenames cannot contain a colon ('.')."
End If
#End If
If Not colonLoc = 0 And slashLoc = 0 And dotLoc = 0 _
And Left(DrivePathFileExt, 1) <> slashStr _
And Left(DrivePathFileExt, 1) <> "." Then
s = "DrivePathFileExt ('" & DrivePathFileExt _
& "') has invalid format. " _
& "Good example: 'C:\folder\file.txt'"
ElseIf colonLoc <> 0 And colonLoc <> 2 Then
' We are on Windows and there is a colon; it can only be
' in position 2.
s = "DrivePathFileExt ('" & DrivePathFileExt _
& "') has invalid format. " _
& "In the Windows operating system, " _
& "a colon (':') can only be the second character '" _
& "of a valid file path. "
ElseIf Left(DrivePathFileExt, 1) = ":" _
Or InStr(3, DrivePathFileExt, ":", vbTextCompare) > 0 Then
'If path contains a drive letter, it must contain at least one slash.
s = "DrivePathFileExt ('" & DrivePathFileExt _
& "') has invalid format. " _
& "Colon can only appear in the second character position." _
& slashStr & "')."
ElseIf colonLoc > 0 And slashLoc = 0 _
And Len(DrivePathFileExt) > 2 Then
'If path contains a drive letter, it must contain at least one slash.
s = "DrivePathFileExt ('" & DrivePathFileExt _
& "') has invalid format. " _
& "The last dot ('.') cannot be before the last file separator '" _
& slashStr & "')."
ElseIf colonLoc = 2 _
And InStr(1, DrivePathFileExt, slashStr, vbTextCompare) = 0 _
And Len(DrivePathFileExt) > 2 Then
' There is a colon, but no file separator (slash). This is invalid.
s = "DrivePathFileExt ('" & DrivePathFileExt _
& "') has invalid format. " _
& "If a drive letter is included, then there must be at " _
& "least one file separator character ('" & slashStr & "')."
ElseIf Len(driveStr) > 0 And Len(DrivePathFileExt) > 2 And slashLoc = 0 Then
' If path contains a drive letter and is more than 2 character long
' (e.g., 'C:'), it must contain at least one slash.
s = "DrivePathFileExt cannot contain a drive letter but no path separator."
End If
If Len(s) > 0 Then
End If
' Determine if DrivePathFileExt = DrivePath
' or = Path (with no fileStr or extStr components).
If Right(DrivePathFileExt, 1) = slashStr _
Or slashLoc = 0 _
Or dotLoc = 0 _
Or (dotLoc > 0 And dotLoc <= slashLoc + 1) Then
' If rightmost character is the slashStr, then no fileExt exists, just drivePath
' If no dot found, then no extension. Assume a folder is after the last slashstr,
' not a filename.
' If a dot is found (extension exists),
' If a rightmost dot appears one-char to the right of the rightmost slash
' or anywhere before (left) of that, it is not a file/ext separator. Exmaple:
' 'C:\folder1\.folder2' Then
' If no slashes, then no fileExt exists. It must just be a driveletter.
' DrivePathFileExt contains no file or ext name.
fileStr = ""
extStr = ""
fileExtStr = ""
pathStr = pathFileExtStr
drivePathStr = DrivePathFileExt
GoTo ReturnResults
Else
' fileStr
fileStr = ""
If slashLoc > 0 Then
If Len(extStr) = 0 Then
fileStr = fileExtStr
Else
' length of filename excluding dot and extension.
i = Len(fileExtStr) - Len(extStr) - 1
fileStr = Left(fileExtStr, i)
End If
Else
s = "Error in FileManagementMod.ParsePath2 function. " _
& "*** Unhandled scenario: find fileStr when slashLoc = 0. *** "
Err.Raise 52, "FileManagementMod.ParsePath2", s
End If
' pathStr
pathStr = ""
' length of pathFileExtStr excluding fileExt.
i = Len(pathFileExtStr) - Len(fileExtStr)
pathStr = Left(pathFileExtStr, i)
' drivePathStr
drivePathStr = ""
' length of DrivePathFileExt excluding dot and extension.
i = Len(DrivePathFileExt) - Len(fileExtStr)
drivePathStr = Left(DrivePathFileExt, i)
End If
ReturnResults:
' ReturnType uses a 4-digit binary code: dpfe = drive path file extension,
' where 1 = return in array and 0 = do not return in array
' -2, and 0 are special cases that do not follow the code.
' Note: pathstr is determined with the tailing slashstr
If Len(drivePathStr) > 0 And Right(drivePathStr, 1) <> slashStr _
Then drivePathStr = drivePathStr & slashStr
If Len(pathStr) > 0 And Right(pathStr, 1) <> slashStr _
Then pathStr = pathStr & slashStr
#If Not Mac Then
' Including this code add a slash to the beginnning where missing.
' the downside is that it would create an absolute path where a
' sub-path of the current folder is intended.
'If colonLoc = 0 Then
' If Len(drivePathStr) > 0 And Not IsIn(Left(drivePathStr, 1), slashStr, ".") _
Then drivePathStr = slashStr & drivePathStr
' If Len(pathStr) > 0 And Not IsIn(Left(pathStr, 1), slashStr, ".") _
Then pathStr = slashStr & pathStr
' If Len(pathFileExtStr) > 0 And Not IsIn(Left(pathFileExtStr, 1), slashStr, ".") _
Then pathFileExtStr = slashStr & pathFileExtStr
'End If
#End If
Select Case ReturnType
Case -2 ' used for ParsePath2Test() only.
ParsePath2 = "DrivePathFileExt " _
& CStr(Nz(DrivePathFileExt, "{empty string}")) _
& vbCrLf & " " _
& "-------------- -----------------------------------------" _
& vbCrLf & " " & "D:\Path\ " & drivePathStr _
& vbCrLf & " " & "\path[\file.ext] " & pathFileExtStr _
& vbCrLf & " " & "\path\ " & pathStr _
& vbCrLf & " " & "file.ext " & fileExtStr _
& vbCrLf & " " & "file " & fileStr _
& vbCrLf & " " & "ext " & extStr _
& vbCrLf & " " & "D " & driveStr _
& vbCrLf & vbCrLf
' My custom debug printer prints to Immediate winodw and log file.
' Dbg.Prnt 2, ParsePath2
Debug.Print ParsePath2
Case 1 '0001: ext
ParsePath2 = extStr
Case 10 '0010: file
ParsePath2 = fileStr
Case 11 '0011: file.ext
ParsePath2 = fileExtStr
Case 100 '0100: path
ParsePath2 = pathStr
Case 110 '0110: (path, file)
ParsePath2 = pathStr & fileStr
Case 111 '0111:
ParsePath2 = pathFileExtStr
Case 1000
ParsePath2 = driveStr
Case 1100
ParsePath2 = drivePathStr
Case 1110
ParsePath2 = drivePathStr & fileStr
Case 1111
ParsePath2 = DrivePathFileExt
Case 1010, 101, 1001
s = "Error in FileManagementMod.ParsePath2 function. " _
& "Value of Paramter (ReturnType = " _
& CStr(ReturnType) & ") is not valid."
Err.Raise 380, "FileManagementMod.ParsePath2", s
Case Else ' default: 0
ParsePath2 = Array(driveStr, pathStr, fileStr, extStr)
End Select
End Function
Supporting function GetPathSeparatorTest extends the native Application.pathSeparator (or bypasses when needed) to work on Mac and Win. It can also takes an optional path string and will try to determine the path separator used in the string (favoring the OS native path separator).
支持函数 GetPathSeparatorTest 扩展了原生 Application.pathSeparator（或在需要时绕过）以在 Mac 和 Win 上工作。它还可以采用可选的路径字符串，并尝试确定字符串中使用的路径分隔符（支持操作系统本机路径分隔符）。
Private Sub GetPathSeparatorTest()
Dim s As String
Debug.Print "GetPathSeparator(s):"
Debug.Print "s not provided: ", GetPathSeparator
s = "C:\folder1\folder2\file.ext"
Debug.Print "s = "; s, GetPathSeparator(DrivePathFileExt:=s)
s = "C:/folder1/folder2/file.ext"
Debug.Print "s = "; s, GetPathSeparator(DrivePathFileExt:=s)
End Sub
Function GetPathSeparator(Optional DrivePathFileExt As String = "") As String
' by Chris Advena
' Finds the path separator from a string, DrivePathFileExt.
' If DrivePathFileExt is not provided, return the operating system path separator
' (Windows = backslash, Mac = forwardslash).
' Mac/Win compatible.
' Initialize
Dim retStr As String: retStr = ""
Dim OSSlash As String: OSSlash = ""
Dim OSOppositeSlash As String: OSOppositeSlash = ""
Dim PathFileExtSlash As String
GetPathSeparator = ""
retStr = ""
' Determine if OS expects fwd or back slash ("/" or "\").
On Error GoTo EH
OSSlash = Application.pathSeparator
If DrivePathFileExt = "" Then
' Input parameter DrivePathFileExt is empty, so use OS file separator.
retStr = OSSlash
Else
' Input parameter DrivePathFileExt provided. See if it contains / or \.
' Set OSOppositeSlash to the opposite slash the OS expects.
OSOppositeSlash = "\"
If OSSlash = "\" Then OSOppositeSlash = "/"
' If DrivePathFileExt does NOT contain OSSlash
' and DOES contain OSOppositeSlash, return OSOppositeSlash.
' Otherwise, assume OSSlash is correct.
retStr = OSSlash
If InStr(1, DrivePathFileExt, OSSlash, vbTextCompare) = 0 _
And InStr(1, DrivePathFileExt, OSOppositeSlash, vbTextCompare) > 0 Then
retStr = OSOppositeSlash
End If
End If
GetPathSeparator = retStr
Exit Function
EH:
' Application.PathSeparator property does not exist in Access,
' so get it the slightly less easy way.
#If Mac Then ' Application.PathSeparator doesn't seem to exist in Access...
OSSlash = "/"
#Else
OSSlash = "\"
#End If
Resume Next
End Function
Supporting function (actually commented out, so you can skip this if you don't plan to use it).
支持函数（实际上已经注释掉了，所以不打算使用的可以跳过）。
Sub IsInTest()
' IsIn2 is case insensitive
Dim StrToFind As String, arr As Variant
arr = Array("Me", "You", "Dog", "Boo")
StrToFind = "doG"
Debug.Print "Is '" & CStr(StrToFind) & "' in list (expect True): " _
, IsIn(StrToFind, "Me", "You", "Dog", "Boo")
StrToFind = "Porcupine"
Debug.Print "Is '" & CStr(StrToFind) & "' in list (expect False): " _
, IsIn(StrToFind, "Me", "You", "Dog", "Boo")
End Sub
Function IsIn(ByVal StrToFind, ParamArray StringArgs() As Variant) As Boolean
' StrToFind: the string to find in the list of StringArgs()
' StringArgs: 1-dimensional array containing string values.
' Built for Strings, but actually works with other data types.
Dim arr As Variant
arr = StringArgs
IsIn = Not IsError(Application.Match(StrToFind, arr, False))
End Function
回答by josef
Use these codes and enjoy it.
使用这些代码并享受它。
Public Function GetDirectoryName(ByVal source As String) As String()
Dim fso, oFolder, oSubfolder, oFile, queue As Collection
Set fso = CreateObject("Scripting.FileSystemObject")
Set queue = New Collection
Dim source_file() As String
Dim i As Integer
queue.Add fso.GetFolder(source) 'obviously replace
Do While queue.Count > 0
Set oFolder = queue(1)
queue.Remove 1 'dequeue
'...insert any folder processing code here...
For Each oSubfolder In oFolder.SubFolders
queue.Add oSubfolder 'enqueue
Next oSubfolder
For Each oFile In oFolder.Files
'...insert any file processing code here...
'Debug.Print oFile
i = i + 1
ReDim Preserve source_file(i)
source_file(i) = oFile
Next oFile
Loop
GetDirectoryName = source_file
End Function
And here you can call function:
在这里你可以调用函数：
Sub test()
Dim s
For Each s In GetDirectoryName("C:\New folder")
Debug.Print s
Next
End Sub
