使用多字符分隔符分割 Java 字符串
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Java String split with multicharacter delimiter
提问by David Homes
I'm fairly new to Java and I thought this worked the same as with other languages.
我对 Java 还很陌生，我认为这与其他语言的工作方式相同。
For a string:
对于字符串：
String line = "3::Daniel::Louis||##2::Leon: the Professional::1994||6::Jean::Reno||7::Gary::Oldman||8::Natalie::Portman||##3::Scarface::1983||9::Al::Pacino||10::Michelle::Pfeiffer";
I want to split it at every ||##.
我想在每个||##.
But:
但：
for(String s : line.split("||##")) {
System.out.println("|"+s+"|");
}
returns:
返回：
||
|3|
|:|
|:|
|D|
|a|
|n|
|i|
... etc.
... 等等。
I was expecting:
我期待：
3::Daniel::Louis
Leon: the Professional
... etc.
... 等等。
What am I doing wrong?
我究竟做错了什么？
回答by gtgaxiola
You have to escape the | character since it's a regex metacharacter for logical OR
你必须逃离| 字符，因为它是逻辑 OR 的正则表达式元字符
So I would use
所以我会用
line.split("\|\|##"))
Note that You have to escape the slash as well that is why I use
请注意，您也必须转义斜线，这就是我使用的原因
\|
instead of
代替
\|
To escape that metacharacter
逃避那个元字符
回答by Clyde
public String[] split(String regex)
回答by paulsm4
It sounds like you want something like this:
听起来你想要这样的东西：
Pattern p = Pattern.compile("\|\|##", Pattern.LITERAL)
String[] result = p.split(myString)
I know you can have multiple characters in your delimiter, and that you can excludeyour delimiter from the output string.
我知道您的分隔符中可以有多个字符，并且您可以从输出字符串中排除您的分隔符。
I don'tknow if the example above will work exactlyfor your scenario; you might have to experiment a bit (for example, "escaping" regex "metacharacters" with "\").
我不知道，如果上面的例子将工作正是为您的方案; 您可能需要进行一些试验（例如，使用“\”“转义”正则表达式“元字符”）。
Here's the Javadoc for Pattern.compile:
这是 Pattern.compile 的 Javadoc：
And here's more information on Java regex syntax:
这里有更多关于 Java 正则表达式语法的信息：
回答by skiller3
Gilberto's solution will work just fine in this case, but you might want to check out guava. It has a lot of very useful utility classes including a String splitter. With it you could write:
Gilberto 的解决方案在这种情况下可以正常工作，但您可能想查看guava。它有许多非常有用的实用程序类，包括字符串拆分器。有了它，你可以写：
Iterable<String> frags = Splitter.on("||##").split(line);
// Do whatever with the iterable...maybe you just want a list?
// List<String> fragList = Lists.newArrayList(frags);
回答by pb2q
You need to escape the bars: |is a special character in the regex.
您需要转义条形：|是正则表达式中的特殊字符。
Use:
利用：
for(String s : line.split("\|\|##")) {
Alternately, you can use \Q\Eto force that the entire pattern be used literally:
或者，您可以使用\Q\E来强制按字面意思使用整个模式：
for(String s : line.split("\Q||##\E")) {
This is probably the same pattern that you'll get from Pattern.quote.
这可能与您从Pattern.quote.
|allows you to specify optional patterns in a regex. Your regex is equivalent to |##, or: nothing OR##. This splits around the empty string, or between every character in the input.
|允许您在正则表达式中指定可选模式。您的正则表达式相当于|##, or: nothing OR##。这将围绕空字符串拆分，或在输入中的每个字符之间拆分。
See the javadocfor Pattern.
请参阅的javadoc的Pattern。
回答by Reimeus
You should escape your |characters:
你应该转义你的|角色：
for (String s : line.split("\|\|##"))
回答by srini.venigalla
You have to escape the '|' like this \|
你必须逃避'|' 像这样\|
