C语言 错误：此处未声明（不在函数中）
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error: undeclared here (not in a function)
提问by Vbp
I am getting this error on the last line of the code, as I am trying to read data from an extra.txt file. Records are read properly from an input.txt but not sure why it is throwing error for extra file. Thanks!
我在代码的最后一行收到此错误，因为我正在尝试从 extra.txt 文件读取数据。从 input.txt 正确读取记录，但不确定为什么它会为额外文件抛出错误。谢谢！
typedef struct {
char* fname;
char* lname;
int id;
int age;
} data;
typedef struct {
data** array;
int len;
int cap;
}vector;
vector* vector_read(FILE* in_file)
{
int i;
vector *v = (vector*)malloc(sizeof(vector));
fscanf(in_file,"%d",&v->len);
if(in_file=NULL)
{
return NULL;
}
printf("%d",v->len);
data** array = (data**)malloc(sizeof(data*)*(v->len));
v->array = array;
data *temp;
for(i=0;i<(v->len);i++)
{
temp = data_read(in_file);
v->array[i] = temp;
}
return v;
}
vector *v = vector_read(input);
printf( "initial state of vector v\n");
vector_print(v);
vector *v_add = vector_read(extra);
EDIT:
编辑：
extra.txt has records in this fashion:
extra.txt 有这种方式的记录：
4
Barak Obama 101 50
Joe Biden 102 55
Joe Plumber 10293 45
Wayne Gretzky 99 56
and input.txt
和输入.txt
1
Aaaa
Aooo
1
20
采纳答案by alk
Your code needs go inside a function.
您的代码需要进入一个函数。
For example like this:
例如像这样：
int read_input_and_extra(FILE * input, FILE * extra)
{
vector *v = vector_read(input);
if (!v)
return -1;
printf( "initial state of vector v\n");
vector_print(v);
vector *v_add = vector_read(extra);
if (!v_add)
return -2;
return 0;
}
