php date() 方法，“遇到格式不正确的数值”不想格式化 $_POST 中传递的日期
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date() method, "A non well formed numeric value encountered" does not want to format a date passed in $_POST
提问by Prefix
I unfortunately can't use DateTime()as the server this project is on is running PHP v.5.2.
不幸的DateTime()是，我无法使用该项目所在的服务器正在运行 PHP v.5.2。
the line in question:
有问题的行：
$aptnDate2 = date('Y-m-d', $_POST['nextAppointmentDate']);
throws the following error:
引发以下错误：
Notice: A non well formed numeric value encountered
so I var dump to make sure it's well formatted..
所以我 var dump 以确保它的格式正确..
var_dump($_POST['nextAppointmentDate']);
string(10) "12-16-2013"
The php docs statethat it takes a timestamp not a string. but when I do:
在PHP的文档说明，它需要一个时间戳不是一个字符串。但是当我这样做时：
date('Y-m-d', strtotime($_POST['nextAppointmentDate']));
and then var_dumpthe result, I get this:
然后var_dump结果，我得到了这个：
string(10) "1969-12-31"
why can I not format a date with this date value and strtotime()?
为什么我不能用这个日期值和 strtotime() 格式化日期？
thanks!
谢谢！
回答by Amal Murali
From the documentation for strtotime():
从文档中strtotime()：
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
m/d/y 或 dmy 格式的日期通过查看各个组件之间的分隔符来消除歧义：如果分隔符是斜杠 (/)，则假定为美国 m/d/y；而如果分隔符是破折号 (-) 或点 (.)，则假定为欧洲 dmy 格式。
In your date string, you have 12-16-2013. 16isn't a valid month, and hence strtotime()returns false.
在您的日期字符串中，您有12-16-2013. 16不是有效月份，因此strtotime()返回false.
Since you can't use DateTime class, you could manually replace the -with /using str_replace()to convert the date string into a format that strtotime()understands:
由于您不能使用 DateTime 类，您可以手动替换-with /usingstr_replace()将日期字符串转换为strtotime()可理解的格式：
$date = '2-16-2013';
echo date('Y-m-d', strtotime(str_replace('-','/', $date))); // => 2013-02-16
