bash 如何将文件上移一个目录并删除旧目录而无需专门命名文件？
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How can I move files up one directory and delete old directory without specifically naming files?
提问by Jeff Severns Guntzel
I use a shell script that takes a single directory, called NewData, with whatever is inside of it, and creates this:
我使用一个 shell 脚本，它接受一个名为 的单个目录NewData，其中包含其中的任何内容，并创建以下内容：
There is one step I want to add, and I am not sure how to do it. I want to move the contents of NewDataand NewDataCopyinto their respective parent directories (ProtectedOrigand Data) and delete NewDataand NewDataCopy. What command(s) would I add to my script to do this without specifically naming the files to be moved (they will be different every time I run the script)?
我想添加一个步骤，我不知道该怎么做。我想移动的内容NewData并NewDataCopy到各自的父目录（ProtectedOrig和Data），并删除NewData和NewDataCopy。我会在脚本中添加哪些命令来执行此操作，而无需专门命名要移动的文件（每次运行脚本时它们都会不同）？
If it would help, you can have a look at the script here. I'm grateful for whatever assistance I can get!
如果有帮助，您可以在此处查看脚本。我很感激我能得到的任何帮助！
回答by drysdam
You can move everything without naming the files specifically by using a "glob" (aka a "wildcard"). That's a *.
您可以使用“glob”（又名“通配符”）移动所有内容而无需专门命名文件。那是一个*。
So let's say you are in DataDirectory. You can move everything from Data/NewDataCopyup to Databy doing this: mv Data/NewDataCopy/* Data/. Then delete with a rmdir Data/NewDataCopy.
因此，假设您在DataDirectory. 您可以通过执行以下操作将所有内容从Data/NewDataCopyup移动到Data：mv Data/NewDataCopy/* Data/。然后用 删除rmdir Data/NewDataCopy。
Starting from DataDirectorythen to do everything you'd do this:
从开始DataDirectory，然后做你会做这一切：
mv Data/NewDataCopy/* Data/
rmdir Data/NewDataCopy
mv ProtectedOrig/NewData/* ProtectedOrig/
rmdir ProtectedOrig/NewData
