Javascript - 按值删除数组项
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Javascript - remove an array item by value
提问by itsme
My situation:
我的情况：
var id_tag = [1,2,3,78,5,6,7,8,47,34,90];
I would like to delete where id_tag = 90and to return:
我想delete where id_tag = 90并返回：
var id_tag = [1,2,3,78,5,6,7,8,47,34];
How can I do that?
我怎样才能做到这一点？
回答by Joseph Silber
You'll want to use JavaScript's Array splicemethod:
你会想要使用 JavaScript 的Arraysplice方法：
var tag_story = [1,3,56,6,8,90],
id_tag = 90,
position = tag_story.indexOf(id_tag);
if ( ~position ) tag_story.splice(position, 1);
P.S.For an explanation of that cool ~tilde shortcut, see this post:
PS有关那个很酷的~波浪号快捷方式的解释，请参阅此帖子：
Using a ~tilde with indexOfto check for the existence of an item in an array.
使用~波浪号 withindexOf检查数组中是否存在某项。
Note:IE < 9 does not support .indexOf()on arrays. If you want to make sure your code works in IE, you should use jQuery's $.inArray():
注意：IE < 9 不支持.indexOf()数组。如果你想确保你的代码在 IE 中工作，你应该使用 jQuery 的$.inArray()：
var tag_story = [1,3,56,6,8,90],
id_tag = 90,
position = $.inArray(id_tag, tag_story);
if ( ~position ) tag_story.splice(position, 1);
If you want to support IE < 9 but don't already have jQuery on the page, there's no need to use it justfor $.inArray. You can use this polyfillinstead.
如果您想支持 IE < 9 但页面上还没有 jQuery，则无需仅将其用于$.inArray. 你可以改用这个 polyfill。
回答by Pete
If you're going to be using this often (and on multiple arrays), extend the Array object to create an unset function.
如果您要经常使用它（并且在多个数组上），请扩展 Array 对象以创建一个未设置的函数。
Array.prototype.unset = function(value) {
if(this.indexOf(value) != -1) { // Make sure the value exists
this.splice(this.indexOf(value), 1);
}
}
tag_story.unset(56)
回答by Eli Grey
tag_story.splice(tag_story.indexOf(id_tag), 1);
回答by Peter Olson
function removeValue(arr, value) {
for(var i = 0; i < arr.length; i++) {
if(arr[i] === value) {
arr.splice(i, 1);
break;
}
}
return arr;
}
This can be called like so:
这可以这样调用：
removeValue(tag_story, 90);
回答by disfated
As a variant
作为变种
delete array[array.indexOf(item)];
If you know nothing about deleteoperator, DON'T use this.
如果您对delete运算符一无所知，请不要使用此.
回答by Aleck Landgraf
I like to use filter:
我喜欢使用过滤器：
var id_tag = [1,2,3,78,5,6,7,8,47,34,90];
// delete where id_tag = 90
id_tag = id_tag.filter(function(x) {
if (x !== 90) {
return x;
}
});
回答by yckart
Here are some helper functions I use:
以下是我使用的一些辅助函数：
Array.contains = function (arr, key) {
for (var i = arr.length; i--;) {
if (arr[i] === key) return true;
}
return false;
};
Array.add = function (arr, key, value) {
for (var i = arr.length; i--;) {
if (arr[i] === key) return arr[key] = value;
}
this.push(key);
};
Array.remove = function (arr, key) {
for (var i = arr.length; i--;) {
if (arr[i] === key) return arr.splice(i, 1);
}
};
回答by J. Holmes
You'll want to use .indexOf()and .splice(). Something like:
你会想要使用.indexOf()和.splice()。就像是：
tag_story.splice(tag_story.indexOf(90),1);
回答by Gourav Sahare
You can use lodash.js
你可以使用 lodash.js
_.pull(arrayName,valueToBeRemove);
_.pull(arrayName,valueToBeRemove);
In your case :- _.pull(id_tag,90);
在你的情况下：- _.pull(id_tag,90);
回答by Siddhartha
var id_tag = [1,2,3,78,5,6,7,8,47,34,90];
var delete_where_id_tag = 90
id_tag =id_tag.filter((x)=> x!=delete_where_id_tag);
