bash 如何在没有换行符的情况下回显内容？
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How to echo out things without a newline?
提问by ricky162
I have the following code...
我有以下代码...
for x in ${array[@]}
do
echo $x
done| sort
The results are something like this
结果是这样的
1
2
3
4
5
Is there a way to print it as 1 2 3 4 5instead? Without adding a newline every time?
有没有办法把它打印出来1 2 3 4 5？每次都不添加换行符？
I also tried printfas suggested by another post, but it's still printing new lines
我也printf按照另一篇文章的建议尝试过，但它仍在打印新行
for x in ${array[@]}
do
printf '%s' "$x"
done| sort
回答by heemayl
Yes. Use the -noption:
是的。使用-n选项：
echo -n $x
From help echo:
来自help echo：
-n do not append a newline
This would strips off the last newline too, so if you want you can add a final newline after the loop:
这也会删除最后一个换行符，因此如果您愿意，可以在循环后添加最后一个换行符：
for ...; do ...; done; echo
Note:
笔记：
This is not portable among various implementations of echobuiltin/external executable. The portable way would be to use printfinstead:
这在echo内置/外部可执行文件的各种实现中是不可移植的。可移植的方式是使用printf：
printf '%s' "$x"
回答by anubhava
You don't need a for loop to sort numbers from an array.
您不需要 for 循环来对数组中的数字进行排序。
Use process substitution like this:
像这样使用进程替换：
sort <(printf "%s\n" "${array[@]}")
To remove new lines use:
要删除新行，请使用：
sort <(printf "%s\n" "${array[@]}") | tr '\n' ' '
回答by PSkocik
printf '%s\n' "${array[@]}" | sort |tr '\n' ' '
printf '%s\n'-- more robust than echoand you want the newlines here for sort's sake
"${array[@]}"-- quotes unnecessary for your particular array, but good practice as you don't generally want word-spliting and glob expansions there
printf '%s\n'-比更强大的echo，你想在这里为新行sort的缘故
"${array[@]}"-不必要的报价为您的特定阵列，但良好的做法，你不一般要字的分裂和水珠扩张有
