如何使用 Bash 递归创建不存在的子目录？
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How to create nonexistent subdirectories recursively using Bash?
提问by Topher Fangio
I am creating a quick backup script that will dump some databases into a nice/neat directory structure and I realized that I need to test to make sure that the directories exist before I create them. The code I have works, but it seems that there is a better way to do it. Any suggestions?
我正在创建一个快速备份脚本，它将一些数据库转储到一个漂亮/整洁的目录结构中，我意识到我需要在创建目录之前进行测试以确保它们存在。我的代码有效，但似乎有更好的方法来做到这一点。有什么建议？
[ -d "$BACKUP_DIR" ] || mkdir "$BACKUP_DIR"
[ -d "$BACKUP_DIR/$client" ] || mkdir "$BACKUP_DIR/$client"
[ -d "$BACKUP_DIR/$client/$year" ] || mkdir "$BACKUP_DIR/$client/$year"
[ -d "$BACKUP_DIR/$client/$year/$month" ] || mkdir "$BACKUP_DIR/$client/$year/$month"
[ -d "$BACKUP_DIR/$client/$year/$month/$day" ] || mkdir "$BACKUP_DIR/$client/$year/$month/$day"
回答by bmargulies
You can use the -pparameter, which is documented as:
您可以使用该-p参数，该参数记录为：
-p, --parents
no error if existing, make parent directories as needed
-p，--父母
如果存在没有错误，请根据需要制作父目录
So:
所以：
mkdir -p "$BACKUP_DIR/$client/$year/$month/$day"
回答by Jonathan Feinberg
$ mkdir -p "$BACKUP_DIR/$client/$year/$month/$day"
回答by y2k-shubham
While existing answers definitely solve the purpose, if your'e looking to replicate nested directory structure under two different subdirectories, then you can do this
虽然现有的答案肯定能解决这个目的，但如果你想在两个不同的子目录下复制嵌套的目录结构，那么你可以这样做
mkdir -p {main,test}/{resources,scala/com/company}
It will create following directory structure under the directory from where it is invoked
它将在调用它的目录下创建以下目录结构
├── main
│?? ├── resources
│?? └── scala
│?? └── com
│?? └── company
└── test
├── resources
└── scala
└── com
└── company
The example was taken from this linkfor creating SBT directory structure
该示例取自此链接，用于创建 SBT 目录结构
回答by nitrohuffer2001
mkdir -p newDir/subdir{1..8}
ls newDir/
subdir1 subdir2 subdir3 subdir4 subdir5 subdir6 subdir7 subdir8
