php 添加到数组值 (+1)
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Add to an array value (+1)
提问by Steven
I have an array
我有一个数组
$hourly = array(
"01" => "0",
"02" => "0",
"03" => "0",
"04" => "0",
"05" => "0",
"06" => "0",
"07" => "0",
"08" => "0",
"09" => "0",
"10" => "0",
"11" => "0",
"12" => "0",
"13" => "0",
"14" => "0",
"15" => "0",
"16" => "0",
"17" => "0",
"18" => "0",
"19" => "0",
"20" => "0",
"21" => "0",
"22" => "0",
"23" => "0"
);
And I have a bunch of data like "01" and "03" and "21" and I want to add (+1) to that specific value in the array. So with the data set "01","03","21","01","22" the resulting array would be
我有一堆数据，如“01”、“03”和“21”，我想将 (+1) 添加到数组中的特定值。因此，对于数据集“01”、“03”、“21”、“01”、“22”，结果数组将是
$hourly = array(
"01" => "2",
"02" => "0",
"03" => "1",
"04" => "0",
"05" => "0",
"06" => "0",
"07" => "0",
"08" => "0",
"09" => "0",
"10" => "0",
"11" => "0",
"12" => "0",
"13" => "0",
"14" => "0",
"15" => "0",
"16" => "0",
"17" => "0",
"18" => "0",
"19" => "0",
"20" => "0",
"21" => "1",
"22" => "1",
"23" => "0"
);
How could I go about doing that? Is there a function to add 1 to an array element?
我怎么能这样做呢？是否有将1添加到数组元素的函数？
回答by Scott
$updates = array("01","03","21","01","22");
foreach($updates as $num) {
$hourly[$num]++;
}
回答by Mark Baker
$hours = array("01", "03", "21" );
foreach($hours as $hour) {
$hourly[$hour] += 1;
}
回答by Artefacto
Normally, you'd be able to do:
通常，您可以执行以下操作：
$array["key"]++;
However, your arrays have a few peculiarities you should fix;
但是，您的阵列有一些您应该修复的特性；
- Your key values are actually strings. If you want numbers you can increment, you should use numbers from the beginning. If you store a string and increment it with the syntax above, it'll be turned into an integer.
- Arrays store string or a numbers as keys. You're using both. "01" will be stored as a string key, "10" will be stored as a number. Consider storing only numbers as keys.
- 您的键值实际上是字符串。如果你想要可以递增的数字，你应该从一开始就使用数字。如果您存储一个字符串并使用上面的语法增加它，它将变成一个整数。
- 数组存储字符串或数字作为键。你两个都用。“01”将存储为字符串键，“10”将存储为数字。考虑只存储数字作为键。
None of these make your script not work, but the inconsistency and unnecessary performance hit are avoidable.
这些都不会使您的脚本无法工作，但可以避免不一致和不必要的性能损失。
回答by rubber boots
You can use a completely "functional" approach, even if it's PHPand even id its not very beautiful ;-) But it works (PHP >= 5.3.0):
您可以使用完全“功能性”的方法，即使它是 PHP，甚至 id 它也不是很漂亮；-) 但它有效（PHP >= 5.3.0）：
...
$fr = 1; $to = 23;
# generate original Array
$hourly = array_combine(
array_map( function($n){return sprintf("%02s",$n);}, range($fr,$to) ), # Keys
array_map( function($n){return 0;}, range($fr,$to) ) # Values
);
$updates = Array('01','03','21','01','22');
# update values based on keys found in $updates
array_walk( $updates, function($u){global $hourly; $hourly[$u]++;} );
...
Regards
问候
rbo
红包
回答by John Parker
If you simply want to increment each element in the array, you could use:
如果您只想增加数组中的每个元素，您可以使用：
<?php
foreach($hourly as &$element) {
$element++;
}
?>
However, if you only want to increment elements that hold a value, you can use:
但是，如果您只想增加包含值的元素，则可以使用：
<?php
foreach($hourly as &$element) {
$element = $element ? $element + 1 : $element;
}
?>
回答by Alan Pearce
You could construct an array with the updated info ($new = array('01' => '02','03' => '01',)etc and then use array_replace($hourly,$new)or array_merge($hourly,$new). There are probably alternative functions too.
您可以使用更新的信息（$new = array('01' => '02','03' => '01',)等）构造一个数组，然后使用array_replace($hourly,$new)or array_merge($hourly,$new)。也可能有替代函数。
