javascript phantomJS - 将参数传递给 JS 文件
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phantomJS - Pass Argument to the JS File
提问by asprin
Right now I'm using the following command to run phantomJS
现在我正在使用以下命令运行 phantomJS
exec('./phantomjs table.js',$op,$er);
table.js
表.js
var page = require('webpage').create();
page.open('table.php', function () {
page.render('table.png');
phantom.exit();
});
This serves the purpose. But now I'm required to work with a dynamic variable, namely date. So is it possible to pass a PHP or Javascript variable inside the execcommand line so that I can use that variable inside table.js?
这达到了目的。但现在我需要使用一个动态变量，即date. 那么是否可以在exec命令行中传递一个 PHP 或 Javascript 变量，以便我可以在其中使用该变量table.js？
Update
更新
I tried modifying my code according to a solution posted here Passing a variable to PhantomJS via exec
我尝试根据此处发布的解决方案修改我的代码通过 exec 将变量传递给 PhantomJS
exec('./phantomjs table.js http://www.yahoo.com',$op,$er);
table.js
表.js
var args = require('system').args;
var page = require('webpage').create();
var address = system.args[1];
page.open(address, function () {
page.render('table.png');
phantom.exit();
});
But this results in 2 problems:
但这会导致两个问题：
- The whole process takes about 3-4 minutes to finish
- After that I get "Server Not Found" message
- 整个过程大约需要3-4分钟完成
- 之后，我收到“找不到服务器”消息
If I remove the modified code, everything works as expected.
如果我删除修改后的代码，一切都会按预期进行。
More Debugging
更多调试
Inside table.jsI used this:
在table.js 中我使用了这个：
var args = require('system').args;
args.forEach(function(arg, i) {
console.log(i+'::'+arg);
});
var page = require('webpage').create();
var address = 'http://www.gmail.com';
page.open(address, function () {
page.render('github.png');
phantom.exit();
});
On running this, my $op(from execcommand) printout out this:
在运行它时，我的$op（来自exec命令）打印输出：
Array ( [0] => 0::table.js [1] => 1::http://www.yahoo.com )
So far so good. But as soon as I put the below code, the same problems are encountered
到现在为止还挺好。但是我一放下面的代码，就遇到了同样的问题
var args = require('system').args;
var page = require('webpage').create();
var address = system.args[1]; // <--- This line is creating problem, the culprit
page.open(address, function () {
page.render('github.png');
phantom.exit();
});
Seems like that is not the correct syntax. Anything obvious that I'm unable to see?
似乎这不是正确的语法。有什么明显我看不到的吗？
采纳答案by asprin
Well, I found an alternative to the above problem. Instead of using
好吧，我找到了上述问题的替代方案。而不是使用
var address = system.args[1];
I'm doing it by following the below modification
我正在按照以下修改进行操作
var args = require('system').args;
var address = '';
args.forEach(function(arg, i) {
if(i == 1)
{
address = arg;
}
});
var page = require('webpage').create();
page.open(address, function () { // <-- use that address variable from above
page.render('github.png');
phantom.exit();
});
回答by darkrat
The problem with your code is a simple oversight.
您的代码的问题是一个简单的疏忽。
You have already stored the args using
您已经使用存储了参数
var args = require('system').args;
So when you need to reference them you only have to do:
因此，当您需要引用它们时，您只需执行以下操作：
var address = args[1];
The use of "system" is looking in a completely different array
“系统”的使用是在一个完全不同的数组中寻找
回答by user3085999
I had to do this and this answers pointed me to find my final answer however as some people expressed here my browser was crashing... I found the problem and solution and thought was worth sharing...
我不得不这样做，这个答案让我找到了我的最终答案，但是正如一些人在这里表达的那样，我的浏览器崩溃了......我找到了问题和解决方案，并认为值得分享......
This will work perfectly fine if:
如果出现以下情况，这将完全正常工作：
exec('phantomjs phdemo.js http://google.com', $o, $e); ?>
var page = require('webpage').create();
var system = require('system');
var address = system.args[1];
page.open(address, function () {
page.render('output.pdf');
phantom.exit();
});
However if you want to pass more than une parameter in the url address for example google.com?searchteext&date=today I found that the character '&' crashes the browser as it expects it as a different command
但是，如果您想在 url 地址中传递多个 une 参数，例如 google.com?searchteext&date=today 我发现字符 '&' 会使浏览器崩溃，因为它期望它作为不同的命令
My solution was to use the same but instead of putting & I used @ sign so the url will look something like google.com?searchteext@date=today
我的解决方案是使用相同的但不是放置 & 我使用了@ 符号，所以网址看起来像 google.com?searchteext@date=today
then at the other end I added a string replace
然后在另一端我添加了一个字符串替换
var address = address.replace(/@/gi,"&");
Then everything works perfectly fine.... There may be other ways of doing it but this worked perfectly for me
然后一切正常......可能还有其他方法可以做到，但这对我来说非常有效
