Python 舍入 pandas.DataFrame 的正确方法？
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The right way to round pandas.DataFrame?
提问by Michael
I want round pandas.DataFrame.
我要圆pandas.DataFrame。
Here is what i have tried so far:
这是我迄今为止尝试过的：
import pandas as pd
data = pd.DataFrame([1.4,2.5,3.8,4.4,5.6],[6.2,7.6,8.8,9.1,0])
print(round(data))
But when i run this code, i get the following error:
但是当我运行此代码时，出现以下错误：
Traceback (most recent call last):
File "C:\Users\*****\Documents\*****\******\****.py", line 3, in <module>
print(round(data))
TypeError: type DataFrame doesn't define __round__ method
What is the right way to round pandas.DataFrame?
什么是圆的正确方法pandas.DataFrame？
采纳答案by behzad.nouri
first, you may want to change the definition of your data frame, something like:
首先，您可能想要更改数据框的定义，例如：
data = pd.DataFrame([[1.4,2.5,3.8,4.4,5.6],[6.2,7.6,8.8,9.1,0]]).T
which results this:
结果如下：
0 1
0 1.4 6.2
1 2.5 7.6
2 3.8 8.8
3 4.4 9.1
4 5.6 0.0
or:
或者：
data = pd.DataFrame({'A':[1.4,2.5,3.8,4.4,5.6],'B':[6.2,7.6,8.8,9.1,0]})
so that you get two columns, otherwise the other list is picked up as index; then:
这样你就得到两列，否则另一个列表被选为索引；然后：
data.apply(pd.Series.round)
or
或者
import numpy as np
data.apply(np.round)
回答by Vincent Claes
Since pandas 0.17.0 you can use
从熊猫 0.17.0 开始，您可以使用
DataFrame.round(decimals=0, *args, **kwargs)
If you want to round your data to 2 decimals do:
如果要将数据四舍五入为 2 位小数，请执行以下操作：
data.round(2)
more info here: http://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.round.html
更多信息：http: //pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.round.html
