Python中列表中浮点数的总和
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Sum of float numbers in a list in Python
提问by Swarup Rajbhandari
I have got float values in s:
我有浮点值s：
p = list(swn.senti_synsets(a))
s = p[0].pos_score()
print(s)
# Output
0.0
0.0
1.0
0.0
0.25
0.25
then I tried, print(sum(s))which gives the error 'float' object is not Iterable.
how to do this ?
然后我尝试了，print(sum(s))这给出了错误“浮动”对象不是可迭代的。这该怎么做 ？
Solution: Strange that I found the answer myself, i dont know but putting the thing of a separate function worked. `
解决方案：奇怪的是我自己找到了答案，我不知道但是把一个单独的函数的东西放在了一边。`
for x in token:
sum_pos=sum_pos+posCheck(x)
sum_neg=sum_neg+negCheck(x)
def posCheck(a):
p=list(swn.senti_synsets(a))
s = p[0].pos_score() return(s)`
def negCheck(a): p=list(swn.senti_synsets(a)) s = p[0].neg_score() return(s)
I couldn't sum up the list, but when I put the function with returntype, it returned the sum of the positive numbers. Thanks to all of you for trying to help.
我无法总结列表，但是当我将函数放入 returntype 时，它返回了正数的总和。感谢你们所有人的帮助。
回答by Dportology
values = [0.0, 0.0, 1.0, 0.0, 0.25, 0.25]
print sum(values)
works fine for me
对我来说很好用
回答by Rakholiya Jenish
You can also use:
您还可以使用：
>>> l=[0.0, 0.0, 1.0, 0.0, 0.25, 0.25]
>>> sum(map(float,l))
1.5
As other said, sum(l)will also work. I don't know why you are getting error with that.
正如其他人所说，sum(l)也将起作用。我不知道你为什么会出错。
One possible reason might be that your list is of string data type. Convert it to float as:
一种可能的原因可能是您的列表是字符串数据类型。将其转换为浮动为：
l = map(float, l)
or
或者
l = [float(i) for i in l]
Then using sum(l)would work properly.
然后使用sum(l)将正常工作。
EDIT: You can convert the sinto list and then sum it.
编辑：您可以将其转换s为列表，然后将其求和。
s = p[0].pos_score()
print sum(list(s))
回答by Dobz
Try this:
尝试这个：
It adds all pos_score()to a list, and then prints the sum.
它将所有内容添加pos_score()到列表中，然后打印总和。
p = list(swn.senti_synsets(a))
s = [x for x in p[0].pos_score()]
print(sum(s))
回答by effort
It is because in your original code, sis not iterable, and you can thus not use sum on a non-iterable object. If you were to add each value from sinto a list, you could sum the list to give you the result you are looking for.
这是因为在您的原始代码中，s不可迭代，因此您不能在不可迭代的对象上使用 sum。如果您要将每个值添加s到列表中，您可以对列表求和以获得您正在寻找的结果。
Not sure the function pos_score()function works, but perhaps you can create and return the list result from that function?
不确定函数pos_score()函数是否有效，但也许您可以从该函数创建并返回列表结果？
回答by Xavi Martínez
def do(*args):
mylist_ = [float("{:.2f}".format(num)) for num in args]
result =(sum(mylist))
return result
print(do(23.32,45,67,54.27))
Result:
结果：
189.59
I hope this will help.
我希望这将有所帮助。
回答by SprigganCG
To sum float from a list , one easy way is to use fsum
要从列表中对浮点数求和，一种简单的方法是使用 fsum
import math
l=[0.0, 0.0, 1.0, 0.0, 0.25, 0.25]
math.fsum(l)
