javascript 如何从 json 对象中删除 $promise 和 $resolved
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How to remove $promise and $resolved from json object
提问by user1184100
I'm using $resource in angular to get json object and its structure is defined below
我在 angular 中使用 $resource 来获取 json 对象,其结构定义如下
[
{
"id": 0,
"name": "Type1"
},
{
"id": 1,
"name": "Type 2"
}
]
after fetching the data .. console.log(jsonObject) gives me
获取数据后.. console.log(jsonObject) 给了我
[Resource, Resource, $promise: Object, $resolved: true]
How can I remove $promise & $resolved from the resulting object ? I tried angular.fromJson(json) but still I see that these objects still exist.
如何从结果对象中删除 $promise & $resolved ?我试过 angular.fromJson(json) 但我仍然看到这些对象仍然存在。
回答by Sergei Panfilov
I'm looking for the same answer, but at this moment I know only this ugly hack:
我正在寻找相同的答案,但此时我只知道这个丑陋的黑客:
To write a func like this:
要编写这样的函数:
function cleanResponse(resp) {
return JSON.parse(angular.toJson(resp));
}
and call it in every single query (ugly, yep):
并在每个查询中调用它(丑陋,是的):
function getSmt() {
Resource.get({}, function (data) {
$scope.some = cleanResponse(data);
}, function (responce) {
//handle error
})
}
I'll be happy if someone would teach me how to do it correctly
如果有人教我如何正确地做,我会很高兴
回答by callmejuggernaut
Example from my project
我的项目中的示例
Diary.getSharedWithMe(function(data) {
delete data.$promise;
delete data.$resolved;
_self.sharedDiariesWithMe = data;
}, function(error) {
console.log(error)
});
回答by Javarome
From this answer, it looks that yourResource.toJSON()
is readily available.
从这个答案来看,它看起来yourResource.toJSON()
很容易获得。
回答by Arthur S.
Right, I've faced the same problem several times and always ended up using $http instead of $resource, however, today I decided to try and deal with this issue. I hope somebody will find this useful one day as well.
是的,我已经多次遇到同样的问题,最终总是使用 $http 而不是 $resource,但是,今天我决定尝试解决这个问题。我希望有一天有人也会发现这很有用。
So, after you receive your object with $promise inside of it, what you do is just use angular.copy(data)
, like so:
因此,在您收到包含 $promise 的对象后,您要做的就是使用angular.copy(data)
,如下所示:
someService.getSomething($scope.someId).$promise.then(function (data) {
if (data) {
$scope.dataWithoutPromise = angular.copy(data);
}
});
After that, you will see that your dataWithoutPromise
just contains the objects that you need, and $promise and $resolved are gone.
之后,您将看到您的dataWithoutPromise
just 包含您需要的对象,而 $promise 和 $resolved 消失了。
回答by Arnaud Huveners
I'm facing the same issue. In fact, you simply have to use the same version of angular and angular-resource and it will work like a charm. Hope it helps !
我面临同样的问题。事实上,你只需要使用相同版本的 angular 和 angular-resource ,它就会像魅力一样工作。希望能帮助到你 !
回答by Geoff
Short answer : angular.fromJson(angular.toJson(resp)); This will remove all "angular specific" functions etc and will return you a clean data object.
简短回答:angular.fromJson(angular.toJson(resp)); 这将删除所有“角度特定”功能等,并将返回一个干净的数据对象。
回答by Mr.Bob
Please simply do this:
请简单地这样做:
jsonObject.$promise = undefined; jsonObject.$resolved = undefined;
jsonObject.$promise = 未定义;jsonObject.$resolved = undefined;
$promise and $resolved will not be removed but you will be able to do what you want.
$promise 和 $resolved 不会被删除,但你可以做你想做的。
回答by Matt Way
Are you using isArray
or .query()
with your $resource
object?
您是在使用isArray
还是.query()
与您的$resource
对象一起使用?
From the $resource docs: isArray – {boolean=} – If true then the returned object for this action is an array.
从 $resource 文档: isArray – {boolean=} – If true then the returned object for this action is an array.
UPDATE:
更新:
If you are using $resource
correctly, some options you have are:
如果您使用$resource
正确,您可以选择的一些选项是:
1) Have the backend return the data contained within an object, eg. { data: [] }
rather than just an array.
1)让后端返回对象中包含的数据,例如。{ data: [] }
而不仅仅是一个数组。
2) If that is not possible, use the callback from the $resource.query()
, eg.
2)如果这是不可能的,请使用来自 的回调$resource.query()
,例如。
MyResource.query({ myParams: 'something'}, function(result) {
// Do something with the plain result
});
回答by Shar678
I did this quick reusable method for angular.toJson(Properties with leading $$ will be stripped):
我为angular.toJson做了这个快速可重用的方法 (以 $$开头的属性将被剥离):
yourApp.factory('Service', ['$resource', function ($resource) {
return $resource('your/rest/api/path');
}]);
yourApp.factory('commonServices', function () {
return {
toJson : function(response){
return JSON.parse(angular.toJson(response));
//*or*
//return angular.toJson(response);
}
});
And then something like this in your controller:
然后在你的控制器中是这样的:
yourApp.controller('Controller', ['$scope', 'Service','commonServices',
function ($scope, Service, commonServices) {
Service.get().then(function (data) {
$scope.myData = commonServices.toJson(data);
});
});
the more simple way is to add angular.toJsonin the controller
更简单的方法是在控制器中添加angular.toJson
yourApp.controller('Controller', ['$scope', 'Service',
function ($scope, Service, commonServices) {
Service.get().then(function (data) {
$scope.myData = angular.toJson(data);
});
});
回答by GedankenNebel
Try to code something like this in your service:
尝试在您的服务中编写这样的代码:
yourApp.factory('Service', ['$resource', function ($resource) {
return $resource('your/rest/api/path');
}]);
And then something like this in your controller:
然后在你的控制器中是这样的:
yourApp.controller('Controller', ['$scope', 'Service', function ($scope, Service) {
Service.get().then(function (data) {
$scope.myData = data;
});
});