bash 从 shell 中的通配符搜索中排除字符串
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Exclude a string from wildcard search in a shell
提问by steigers
I am trying to exclude a certain string from a file search.
我试图从文件搜索中排除某个字符串。
Suppose I have a list of files: file_Michael.txt, file_Thomas.txt, file_Anne.txt.
假设我有一个文件列表：file_Michael.txt、file_Thomas.txt、file_Anne.txt。
I want to be able and write something like
我希望能够写出类似的东西
ls *<and not Thomas>.txt
to give me file_Michael.txt and file_Anne.txt, but not file_Thomas.txt.
给我 file_Michael.txt 和 file_Anne.txt，而不是 file_Thomas.txt。
The reverse is easy:
反过来很容易：
ls *Thomas.txt
Doing it with a single character is also easy:
使用单个字符也很容易：
ls *[^s].txt
But how to do it with a string?
但是如何用字符串来做呢？
Sebastian
塞巴斯蒂安
回答by Mark Byers
You can use find to do this:
您可以使用 find 来做到这一点：
$ find . -name '*.txt' -a ! -name '*Thomas.txt'
回答by ghostdog74
回答by tripleee
If you are looping a wildcard, just skip the rest of the iteration if there is something you want to exclude.
如果您正在循环使用通配符，如果您想排除某些内容，只需跳过迭代的其余部分。
for file in *.txt; do
case $file in *Thomas*) continue;; esac
: ... do stuff with "$file"
done
