Python 使用 url_for 链接到 Flask 静态文件
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Link to Flask static files with url_for
提问by user1431282
How do you use url_forin Flask to reference a file in a folder? For example, I have some static files in the staticfolder, some of which may be in subfolders such as static/bootstrap.
你如何url_for在 Flask 中使用来引用文件夹中的文件？例如，我在static文件夹中有一些静态文件，其中一些可能在子文件夹中，例如static/bootstrap.
When I try to serve a file from static/bootstrap, I get an error.
当我尝试从 提供文件时static/bootstrap，出现错误。
<link rel=stylesheet type=text/css href="{{ url_for('static/bootstrap', filename='bootstrap.min.css') }}">
I can reference files that aren't in subfolders with this, which works.
我可以引用不在子文件夹中的文件，这很有效。
<link rel=stylesheet type=text/css href="{{ url_for('static', filename='bootstrap.min.css') }}">
What is the correct way to reference static files with url_for? How do I use url_forto generate urls to static files at any level?
引用静态文件的正确方法是什么url_for？我如何使用url_for生成任何级别的静态文件的 url？
采纳答案by tbicr
You have by default the staticendpointfor static files. Also Flaskapplication has the following arguments:
默认情况下，您拥有静态文件的static端点。还Flask应用有以下参数：
static_url_path: can be used to specify a different path for the static files on the web. Defaults to the name of the static_folderfolder.
static_url_path: 可用于为网络上的静态文件指定不同的路径。默认为static_folder文件夹的名称。
static_folder: the folder with static files that should be served at static_url_path. Defaults to the 'static' folder in the root path of the application.
static_folder：包含静态文件的文件夹，应在static_url_path. 默认为应用程序根路径中的“静态”文件夹。
It means that the filenameargument will take a relative path to your file in static_folderand convert it to a relative path combined with static_url_default:
这意味着该filename参数将采用您的文件的相对路径static_folder，并将其转换为与static_url_default以下组合的相对路径：
url_for('static', filename='path/to/file')
will convert the file path from static_folder/path/to/fileto the url path static_url_default/path/to/file.
将文件路径 fromstatic_folder/path/to/file转换为 url path static_url_default/path/to/file。
So if you want to get files from the static/bootstrapfolder you use this code:
因此，如果您想从static/bootstrap文件夹中获取文件，请使用以下代码：
<link rel="stylesheet" type="text/css" href="{{ url_for('static', filename='bootstrap/bootstrap.min.css') }}">
Which will be converted to (using default settings):
将转换为（使用默认设置）：
<link rel="stylesheet" type="text/css" href="static/bootstrap/bootstrap.min.css">
Also look at url_fordocumentation.
另请查看url_for文档。
回答by Andrew Grow
In my case I had special instruction into nginx configuration file:
就我而言，我对 nginx 配置文件有特殊说明：
location ~ \.(js|css|png|jpg|gif|swf|ico|pdf|mov|fla|zip|rar)$ {
try_files $uri =404;
}
All clients have received '404' because nginx nothing known about Flask.
所有客户端都收到了“404”，因为 nginx 对 Flask 一无所知。
I hope it help someone.
我希望它可以帮助某人。
