Python 用键打印字典中的最高值
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print highest value in dict with key
提问by Nishant Nawarkhede
My dict is like,
我的字典就像，
{'A':4,'B':10,'C':0,'D':87}
I want to find max value with its key and min value with its key.
我想用它的键找到最大值，用它的键找到最小值。
Output will be like ,
输出将像，
max : 87 , key is D
最大值 : 87 , 键是 D
min : 0 , key is C
min : 0 , 键是 C
I know how to get min and max values from dict. Is there is any way to get value and key in one statement?
我知道如何从 dict 中获取最小值和最大值。有没有办法在一个语句中获取值和键？
max([i for i in dic.values()])
min([i for i in dic.values()])
采纳答案by Alex Thornton
回答by Hackaholic
just :
只是 ：
mydict = {'A':4,'B':10,'C':0,'D':87}
max(mydict.values())
min(mydict.values())
valueswill give you list of values from the dictionary. maxfunction gives max value. minfunction minimum value
values将为您提供字典中的值列表。max函数给出最大值。min函数最小值
and you want to get key
你想得到钥匙
回答by holdenweb
The clue is to work with the dict's items (i.e.key-value pair tuples). Then by using the second element of the item as the maxkey (as opposed to the dictkey) you can easily extract the highest value and its associated key.
线索是使用字典的项目（即键值对元组）。然后通过使用项目的第二个元素作为max键（而不是dict键），您可以轻松提取最高值及其关联键。
mydict = {'A':4,'B':10,'C':0,'D':87}
>>> max(mydict.items(), key=lambda k: k[1])
('D', 87)
>>> min(mydict.items(), key=lambda k: k[1])
('C', 0)
