java 警告：SQL 错误：1064，SQLState：42000
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时间：2020-11-01 02:08:46 来源:igfitidea点击:
WARN: SQL Error: 1064, SQLState: 42000
提问by Blejzer
I have a problem with hibernate query.
我有休眠查询的问题。
UPDATE: When I use this query it works like a charm:
更新：当我使用这个查询时，它就像一个魅力：
public static List<Korisnik> UzmiSveKorisnike()
{
EntityManager em = Konekcija.getEmf().createEntityManager();
TypedQuery<Korisnik> q = em.createQuery("select k from Korisnik k where k.isActive = 1", Korisnik.class);
List<Korisnik> resultList = q.getResultList();
em.close();
return resultList;
}
But when I use one listed below, to select single result (like for login)...
但是当我使用下面列出的一个时，选择单个结果（如登录）......
I get this error: WARN: SQL Error: 1064, SQLState: 42000
我收到此错误：警告：SQL 错误：1064，SQLState：42000
I have tried variety of ways to implement this query, but without success. I will list them at the end of the post.
我尝试了多种方法来实现此查询，但都没有成功。我会在文章末尾列出它们。
This is the code:
这是代码：
public static Korisnik ProvjeraKorisnickihPodataka(String kIme, String kLozinka)
{
EntityManager em = Konekcija.getEmf().createEntityManager();
{
TypedQuery<Korisnik> q = em.createQuery("select k from Korisnik k where k.isActive = 1 AND k.korisnickoIme=:ime AND k.lozinka =:lozinka", Korisnik.class);
q.setParameter("ime", kIme);
q.setParameter("lozinka", kLozinka);
Korisnik provjeren = q.getSingleResult();
em.close();
return provjeren;
Even if I replace :ime and :lozinka with actual data like "k.korisnickoIme='msbtest' and k.lozinka = 'msbtest'" I get the same error.
即使我将 :ime 和 :lozinka 替换为“k.korisnickoIme='msbtest' and k.lozinka = 'msbtest'”之类的实际数据，我也会收到同样的错误。
Your help is appreciated.
感谢您的帮助。
Thank you!
谢谢！
Complete stack:
完整的堆栈：
Hibernate: select TOP(?) korisnik0_.KorisnikID as KorisnikID11_, korisnik0_.agencija_AgencijaID as agencija8_11_, korisnik0_.ime as ime11_, korisnik0_.isActive as isActive11_, korisnik0_.kontakt as kontakt11_, korisnik0_.korisnickoIme as korisnic5_11_, korisnik0_.lozinka as lozinka11_, korisnik0_.prezime as prezime11_, korisnik0_.rola_RolaID as rola9_11_ from Korisnik korisnik0_ where korisnik0_.isActive=1 and korisnik0_.korisnickoIme=? and korisnik0_.lozinka=?
Jul 05, 2013 11:45:22 AM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
WARN: SQL Error: 1064, SQLState: 42000
Jul 05, 2013 11:45:22 AM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.KorisnikID as KorisnikID11_, korisnik0_.agencija_AgencijaID as agencija8_11_, k' at line 1
javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.KorisnikID as KorisnikID11_, korisnik0_.agencija_AgencijaID as agencija8_11_, k' at line 1
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1377)
at org.hibernate.ejb.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1300)
at org.hibernate.ejb.QueryImpl.getSingleResult(QueryImpl.java:318)
at Servis.LoginServis.ProvjeraKorisnickihPodataka(LoginServis.java:35)
at UI.LogInFrm.do_btnPrijava_widgetSelected(LogInFrm.java:173)
at UI.LogInFrm.widgetSelected(LogInFrm.java:121)
at org.eclipse.swt.widgets.TypedListener.handleEvent(Unknown Source)
at org.eclipse.swt.widgets.EventTable.sendEvent(Unknown Source)
at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source)
at org.eclipse.swt.widgets.Display.runDeferredEvents(Unknown Source)
at org.eclipse.swt.widgets.Display.readAndDispatch(Unknown Source)
at UI.LogInFrm.main(LogInFrm.java:44)
Caused by: org.hibernate.exception.SQLGrammarException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.KorisnikID as KorisnikID11_, korisnik0_.agencija_AgencijaID as agencija8_11_, k' at line 1
at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:125)
at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:110)
at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:129)
at org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:81)
at com.sun.proxy.$Proxy10.executeQuery(Unknown Source)
at org.hibernate.loader.Loader.getResultSet(Loader.java:1926)
at org.hibernate.loader.Loader.executeQueryStatement(Loader.java:1727)
at org.hibernate.loader.Loader.doQuery(Loader.java:852)
at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:293)
at org.hibernate.loader.Loader.doList(Loader.java:2411)
at org.hibernate.loader.Loader.doList(Loader.java:2397)
at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2227)
at org.hibernate.loader.Loader.list(Loader.java:2222)
at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:470)
at org.hibernate.hql.internal.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:355)
at org.hibernate.engine.query.spi.HQLQueryPlan.performList(HQLQueryPlan.java:195)
at org.hibernate.internal.SessionImpl.list(SessionImpl.java:1247)
at org.hibernate.internal.QueryImpl.list(QueryImpl.java:101)
at org.hibernate.ejb.QueryImpl.getSingleResult(QueryImpl.java:285)
... 9 more
Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.KorisnikID as KorisnikID11_, korisnik0_.agencija_AgencijaID as agencija8_11_, k' at line 1
at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method)
at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source)
at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source)
at java.lang.reflect.Constructor.newInstance(Unknown Source)
at com.mysql.jdbc.Util.handleNewInstance(Util.java:411)
at com.mysql.jdbc.Util.getInstance(Util.java:386)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1053)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4096)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:4028)
at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:2490)
at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2651)
at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2734)
at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2155)
at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:2322)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:122)
... 25 more
mapping goes like this:
映射是这样的：
/**
** Class Korisnik
**/
@Entity
public class Korisnik implements Serializable {
//Fields
@Id
@GeneratedValue
private Integer KorisnikID;
private String ime;
private String prezime;
private String kontakt;
private String korisnickoIme;
private String lozinka;
private Boolean isActive;
@JoinColumn(nullable = false)
@ManyToOne
private Agencija agencija;
@JoinColumn(nullable = false)
@ManyToOne
private Rola rola;
and getters and setters go...
和 getter 和 setter 去......
OK, my persistence.xml file looks like this:
好的，我的 persistence.xml 文件如下所示：
<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" version="2.0"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd">
<persistence-unit name="MojaOznaka1" transaction-type="RESOURCE_LOCAL">
<exclude-unlisted-classes>false</exclude-unlisted-classes>
<properties>
<!-- Podaci o bazi podataka -->
<property name="javax.persistence.jdbc.url" value="jdbc:mysql://xxxxxxxxx.xxxxxxxxx.xxx/xxxxxxxxx/" />
<property name="javax.persistence.jdbc.user" value="xxxxxx" />
<property name="javax.persistence.jdbc.password" value="xxxxxx" />
<property name="javax.persistence.jdbc.driver" value="com.mysql.jdbc.Driver" />
<!-- hiberante dialect -->
<property name="hibernate.dialect" value="org.hibernate.dialect.SQLServer2008Dialect" />
<!-- JDBC connection pool (use the built-in) -->
<property name="connection.pool_size" value="1" />
<!-- Ispis SQL koda u konzolu -->
<property name="hibernate.show_sql" value="true" />
<!-- formatiranje SQL koda ispisanog u konzolni prozor -->
<property name="hibernate.format_sql" value="false" />
<!-- Vrijednost "update" kreira tabele ako nepostoje -->
<!-- <property name="hibernate.hbm2ddl.auto" value="update" /> -->
<!-- Enable Hibernate's automatic session context management -->
<property name="current_session_context_class" value="thread" />
<!-- Disable the second-level cache -->
<property name="cache.provider_class" value="org.hibernate.cache.NoCacheProvider" />
<!-- automatsko prepoznavanje JPA klasa -->
<property name="hibernate.archive.autodetection" value="class, hbm" />
</properties>
</persistence-unit>
</persistence>
OK, now what???
好的，现在呢？？？
采纳答案by mabi
The query output you give suggests you told Hibernate to generate SQL for a MS-SQL Server (using TOP(1)to fetch the topmost row).
您提供的查询输出表明您告诉 Hibernate 为 MS-SQL Server 生成 SQL（TOP(1)用于获取最上面的行）。
Since you're using a mysql database as a backend, that won't work. Try adding
由于您使用 mysql 数据库作为后端，所以这行不通。尝试添加
<property name="hibernate.dialect" value="org.hibernate.dialect.MySQLDialect"/>
to your persistence.xml or wherever you configure JPA.
到您的persistence.xml 或您配置JPA 的任何地方。
As @Secko mentions in the comment, omitting the dialect altogether might even select a better (more specific) one.
正如@Secko 在评论中提到的，完全省略方言甚至可能选择更好（更具体）的方言。
回答by ssindelar
This error usually indicates some mapping error. Are all fields used in the where are actually fields of the "Korisnik" class? HQL uses the field names and not the column names from the database.
此错误通常表示某些映射错误。是否在“Korisnik”类的实际字段中使用了所有字段？HQL 使用字段名称而不是数据库中的列名称。
