javascript 如何将 ESLint no-unused-vars 用于代码块？
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How can I use ESLint no-unused-vars for a block of code?
提问by Radex
I need to disable some variable checks in ESLint.
我需要在ESLint.
Currently, I am using this code, but am not getting the desired result:
目前，我正在使用此代码，但没有得到想要的结果：
/* eslint no-unused-vars: ["error", { "caughtErrorsIgnorePattern": "Hey" }] */
export type Hey = {
a: string,
b: object
}
Two questions:
两个问题：
- Is there a variant which can enable
no-unused-varsfor a block of code?
- 是否有可以启用
no-unused-vars代码块的变体？
Something like...
就像是...
/* eslint rule disable"*/
// I want to place my block of code, here
/* eslint rule disable"*/
- Or could I make
Heya global variable so that it can be ignored everywhere?
- 或者我可以创建
Hey一个全局变量以便在任何地方都可以忽略它吗？
回答by Ville Ven?l?inen
Just use pair of lines:
只需使用一对线：
/* eslint-disable no-unused-vars */
// ... your code here with unused vars...
/* eslint-enable no-unused-vars */
回答by zdolny
Alternatively, you can disable the rule for one line:
或者，您可以禁用一行的规则：
// Based on your Typescript example
export type Hey = { // eslint-disable-line no-unused-vars
a: string,
b: object
}
回答by Martin
One more option...
还有一种选择……
function doStuff({
// eslint-disable-next-line no-unused-vars
unused,
usedA,
usedB
}) {
回答by Tim J
For typescript eslint users just add this at the end of line you wish to ignore:
对于打字稿 eslint 用户，只需在您希望忽略的行尾添加：
// eslint-disable-line @typescript-eslint/no-unused-vars
